问题
这是我有的JSON字符串 -
{"attributes":[{"nm":"ACCOUNT","lv":[{"v":{"Id":null,"State":null},"vt":"java.util.Map","cn":1}],"vt":"java.util.Map","status":"SUCCESS","lmd":13585},{"nm":"PROFILE","lv":[{"v":{"Party":null,"Ads":null},"vt":"java.util.Map","cn":2}],"vt":"java.util.Map","status":"SUCCESS","lmd":41962}]}
我需要将上面的JSON字符串转换为Pretty Print JSON输出(使用Jackson),如下所示 -
{
"attributes": [
{
"nm": "ACCOUNT",
"lv": [
{
"v": {
"Id": null,
"State": null
},
"vt": "java.util.Map",
"cn": 1
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 13585
},
{
"nm": "PROFILE
"lv": [
{
"v": {
"Party": null,
"Ads": null
},
"vt": "java.util.Map",
"cn": 2
}
],
"vt": "java.util.Map",
"status": "SUCCESS",
"lmd": 41962
}
]
}
任何人都可以为我上面的例子提供一个示例基础吗?如何实现这种情况,我知道有很多例子,但我无法正确理解这些。通过一个简单的例子可以获得任何帮助。
更新:
以下是我正在使用的代码
ObjectMapper mapper = new ObjectMapper();
System.out.println(mapper.defaultPrettyPrintingWriter().writeValueAsString(jsonString));
但这不适用于我需要输出的方式,如上所述
这是我用于上述JSON的POJO-
public class UrlInfo implements Serializable {
private List<Attributes> attribute;
}
class Attributes {
private String nm;
private List<ValueList> lv;
private String vt;
private String status;
private String lmd;
}
class ValueList {
private String vt;
private String cn;
private List<String> v;
}
谁能告诉我是否为JSON获得了正确的POJO?
**更新: - **
String result = restTemplate.getForObject(url.toString(), String.class);
ObjectMapper mapper = new ObjectMapper();
Object json = mapper.readValue(result, Object.class);
String indented = mapper.defaultPrettyPrintingWriter().writeValueAsString(json);
System.out.println(indented);//This print statement show correct way I need
model.addAttribute("response", (indented));
下面的行打印出类似这样的东西 -
System.out.println(indented);
{
"attributes" : [ {
"nm" : "ACCOUNT",
"error" : "null SYS00019CancellationException in CoreImpl fetchAttributes\n java.util.concurrent.CancellationException\n\tat java.util.concurrent.FutureTask$Sync.innerGet(FutureTask.java:231)\n\tat java.util.concurrent.FutureTask.",
"status" : "ERROR"
} ]
}
这是我需要展示的方式。但是当我把它添加到这样的模型时 -
model.addAttribute("response", (indented));
然后在结果表jsp页面中显示出来,如下所示 -
<fieldset>
<legend>Response:</legend>
<strong>${response}</strong>
</fieldset>
我得到这样的东西 -
{ "attributes" : [ { "nm" : "ACCOUNT", "error" : "null
SYS00019CancellationException in CoreImpl fetchAttributes\n
java.util.concurrent.CancellationException\n\tat
java.util.concurrent.FutureTask$Sync.innerGet(FutureTask.java:231)\n\tat
java.util.concurrent.FutureTask.", "status" : "ERROR" } ] }
我不需要。我需要它打印出来的方式。谁能告诉我为什么会这样发生?
#1 热门回答(146 赞)
要缩进任何旧的JSON,只需将其绑定为Object
,如:
Object json = mapper.readValue(input, Object.class);
然后用缩进写出来:
String indented = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(json);
这可以避免你必须定义实际的POJO来映射数据。
或者你也可以使用JsonNode
(JSON树)。
#2 热门回答(92 赞)
最简单也是最紧凑的解决方案(适用于v2.3.3):
ObjectMapper mapper = new ObjectMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT);
#3 热门回答(20 赞)
使用Jackson 1.9的新方法如下:
Object json = OBJECT_MAPPER.readValue(diffResponseJson, Object.class);
String indented = OBJECT_MAPPER.writerWithDefaultPrettyPrinter()
.writeValueAsString(json);
输出将正确格式化!