问题

我正在尝试从"用户"表中获取所有用户的列表,我收到以下错误:

org.hibernate.hql.internal.ast.QuerySyntaxException: users is not mapped [from users]
org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:180)
org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:110)
org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:93)

这是我写的添加/获取用户的代码:

public List<User> getUsers() {
    Session session = HibernateUtil.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    List<User> result = (List<User>) session.createQuery("from users").list();
    session.getTransaction().commit();
    return result;
}

public void addUser(User user) {
    Session session = HibernateUtil.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    session.save(user);
    session.getTransaction().commit();
}

public void addUser(List<User> users) {
    Session session = HibernateUtil.getSessionFactory().getCurrentSession();
    session.beginTransaction();
    for (User user : users) {
        session.save(user);
    }
    session.getTransaction().commit();
}

添加用户是有效的,但是当我使用getUsers函数时,我得到了这些错误。

这是我的hibernate配置文件:

<hibernate-configuration>
<session-factory>
    <property name="connection.url">jdbc:mysql://localhost:3306/test</property>
    <property name="connection.username">root</property>
    <property name="connection.password">root</property>
    <property name="connection.driver_class">com.mysql.jdbc.Driver</property>
    <property name="hibernate.default_schema">test</property>
    <property name="dialect">org.hibernate.dialect.MySQL5Dialect</property>

    <property name="show_sql">true</property>

    <property name="format_sql">true</property>
    <property name="hbm2ddl.auto">create-drop</property>

    <!-- JDBC connection pool (use the built-in) -->
    <property name="connection.pool_size">1</property>
    <property name="current_session_context_class">thread</property>

    <!-- Mapping files will go here.... -->

    <mapping class="model.Company" />
    <mapping class="model.Conference" />
    <mapping class="model.ConferencesParticipants" />
    <mapping class="model.ConferenceParticipantStatus" />
    <mapping class="model.ConferencesUsers" />
    <mapping class="model.Location" />
    <mapping class="model.User" />

</session-factory>

这是我的用户类:

@Entity
@Table( name = "Users" )
public class User implements Serializable{

    private long userID;
    private int pasportID;
    private Company company; 
    private String name;
    private String email;
    private String phone1;
    private String phone2;
    private String password; //may be null/empty , will be kept hashed
    private boolean isAdmin;
    private Date lastLogin;

    User() {} //not public on purpose!

    public User(int countryID, Company company, String name, String email,
            String phone1, String phone2, String password, boolean isAdmin) {
        this.pasportID = countryID;
        this.company = company;
        this.name = name;
        this.email = email;
        this.phone1 = phone1;
        this.phone2 = phone2;
        this.password = password;
        this.isAdmin = isAdmin;
    }

    @Id
    @GeneratedValue(generator="increment")
    @GenericGenerator(name="increment", strategy = "increment")
    public long getUserID() {
        return userID;
    }
    public void setUserID(long userID) {
        this.userID = userID;
    }
    ...    
}

知道为什么我会收到此错误吗?


#1 热门回答(236 赞)

在HQL中,你应该使用java类名称属性名称of mapped@Entity而不是实际的表名和列名,因此HQL应该是:

List<User> result = (List<User>) session.createQuery("from User").list();

#2 热门回答(21 赞)

例如:你的bean类名称是UserDetails

Query query = entityManager. createQuery("Select UserName from**UserDetails**");

你没有在Db.上给出你的表名,你给出了bean的类名。


#3 热门回答(12 赞)

只是为了分享我的发现。即使查询的目标是正确的类名,我仍然会遇到相同的错误。后来我意识到我从错误的包中导入了Entity类。

我从以下位置更改导入行后问题得以解决:

import org.hibernate.annotations.Entity;

import javax.persistence.Entity;

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