我希望你可以帮助我,我试图制作一个django帖子形式而无需使用ajax重新加载页面,但是我在提交时收到错误500,你能帮我解决这个问题,这是我的代码:
models.py
class ProductoConcepto(models.Model):
producto = models.ForeignKey(Producto)
orden = models.ForeignKey(Cobro)
cantidad = models.FloatField()
urls.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
from cobro import views
urlpatterns = [
url(r'^cobro/agregar_concepto/$', views.addconcept_product, name='add_concepto'),
]
views.py
def addconcept_product(request):
if request.method == 'POST':
if form.is_valid():
producto = request.POST['producto']
orden = request.POST['orden']
cantidad = request.POST['cantidad']
ProductoConcepto.objects.create(producto=producto, orden=orden, cantidad=cantidad)
return HttpResponse('')
模板
<div class="modal inmodal fade" id="myModal1" tabindex="-1" role="dialog" aria-hidden="true">
<div class="modal-dialog modal-m">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">
<span aria-hidden="true">×</span>
<span class="sr-only">Cerrar</span>
</button>
<h3 class="modal-title">Agregar nuevo concepto</h3>
</div>
<div class="modal-body">
<p>Datos de concepto a agregar:</p>
<div class="doctorformstyle">
<form id='formulario-modal' method='post' enctype='multipart/form-data'>
{% csrf_token %}
<ul>{{form2.as_p}}</ul>
<!-- rendered form2 fields: <select id="id_producto" name="producto"><option value="1" selected="selected">object</option></select> -->
<!-- form2 fields: <select id="id_orden" name="orden">
<option value="1" selected="selected">object</option>
</select> -->
<!-- form2 fields: <input id="id_cantidad" name="cantidad" step="any" type="number"> -->
<div class="row align-center">
<input type='submit' name="save1" value='Guardar' class="btn btn-w-m btn-primary"/>
</div>
</form>
</div>
</div>
</div>
</div>
</div>
<script type="text/javascript">
$(document).on('submit', '#formulario-modal', function(e){
e.preventDefault();
$.ajax ({
type: 'POST',
url: '{% url 'add_concepto' %}',
data: {
producto: $('#id_producto').val(),
orden: $('#id_orden').val(),
cantidad: $('#id_cantidad').val(),
csrfmiddlewaretoken: '{{ csrf_token }}',
},
sucess:function(){
alert("OK");
}
})
});
</script>
这是错误:POST http://127.0.0.1:8000/cobro/agregar_concepto/ 500(内部服务器错误)
我想也许在我看来可能缺少某些东西,买我不知道,你能帮助我吗?
编辑:添加了回溯
环境:请求方法:GET请求URL:http://127.0.0.1:8000 / coobro / agregar_concepto / Django版本:1.9.7 Python版本:2.7.11已安装的应用程序:('django.contrib.admin','django .contrib.auth','django.contrib.contenttypes','django.contrib.sessions','django.contrib.messages','django.contrib.staticfiles','entrada','cobro','catalogo', 'selectize','smart_selects')已安装的中间件:('django.contrib.sessions.middleware.SessionMiddleware','django.middleware.common.CommonMiddleware','django.middleware.csrf.CsrfViewMiddleware','django.contrib.auth .middleware.AuthenticationMiddleware','django.contrib.auth.middleware.SessionAuthenticationMiddleware','django.contrib.messages.middleware.MessageMiddleware','django.middleware.clickjacking.XFrameOptionsMiddleware')Traceback:File“C:\ Python27 \ lib get_response中的\ site-packages \ django \ core \ handlers \ base.py“ . %(callback.module,view_name))异常类型:/ cobro / agregar_concepto上的ValueError /异常值:Th e view cobro.views.addconcept_product未返回HttpResponse对象 . 它返回了None .
3 回答
您查看的内容不完整:由于异常状态:视图cobro.views.addconcept_product未返回正确的HttpResponse对象 .
您是否正在查看在新窗口中提供的例外情况?因为它显示“请求方法:GET”,这不应该通过你的ajax函数发生 .
将您的视图修改为:
用类似的东西更新你的return语句 .
此外,当您使用ajax时,您还可以返回JsonResponse .
先导入它
然后返回你的回复
如果方法不是POST,并且您正在提交GET请求,那么会引发异常,因为您没有处理该条件 .
处理无效表单的情况,如果方法不是POST .
还使用ajax方法属性而不是类型 .