我没有xml文档的xsd文件,所以我必须更改为默认的xmlns“http://www.w3.org/2001/XMLSchema-instance " to pars the XML elements but there is a problem to do it, when I change xmlns attribute of root element (myroot) another attribute (xmlns) is created in the child element (data) with the value " myxsd.xsd” . 我想忽略或更改xmlns(myxsd.xsd)的值来正确解析文档 .
我的XML输入:
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<myroot xmlns="myxsd.xsd" class="15">
<data att1="all" att2="actual">
<myobject patt1="patt1_value" patt2="patt2_value" patt3="patt3_value">
<p name="p1">page1</p>
<p name="p2">page1</p>
<p name="p3">page1</p>
<p name="p4">page4</p>
</myobject>
</data>
</myroot>
我的XML输出:
<?xml version="1.0" encoding="UTF-8"?>
<myroot xmlns="http://www.w3.org/2001/XMLSchema-instance" class="15">
<data xmlns="myxsd.xsd" att1="all" att2="actual">
<myobject patt1="patt1_value" patt2="patt2_value" patt3="patt3_value">
<p name="p1">page1</p>
<p name="p2">page1</p>
<p name="p3">page1</p>
<p name="p4">page4</p>
</myobject>
</data>
</myroot>
我的代码:
public void Edit_file() throws JDOMException, IOException {
InputStream in = new FileInputStream("C:\\small_test.xml");
SAXBuilder builder = new SAXBuilder();
Document document = builder.build(in);
// getting the root element
Element root = document.getRootElement();
Namespace tempNamespace = Namespace.getNamespace("http://www.w3.org/2001/XMLSchema-instance");
root.setNamespace(tempNamespace);
// iterating over the children
List<Element> data = root.getChildren("data");
for (Element element : data) {
Attribute id = element.getAttribute("att1");
id.setValue("New value");
}
XMLOutputter xmlOutput = new XMLOutputter();
xmlOutput.setFormat(Format.getPrettyFormat());
xmlOutput.output(document, System.out);
}
1 回答
我真的不明白你为什么要将元素移动到不同的命名空间(尤其是命名空间
http://www.w3.org/2001/XMLSchema-instance
,这不是为了这个目的),但如果你想这样做,你必须改变所有的元素,而不仅仅是最外层的 . 尽管名称空间声明仅出现在最外层元素上,但它具有将所有元素放在此命名空间中的效果,除非您更改它们,否则它们将保留在该命名空间中 .