我正在使用eclipse Version:Neon.3 Release(4.6.3)和Tomcat(v8.5)来做Java(JDK1.8)编程 .
我收到一个错误:
cvc-complex-type.2.4.a:从元素'location'开始发现无效内容 . 其中一个'{“http:// java.sun.com/xml/ns/javaee":error-code,"http://java.sun.com/xml/ns/javaee":exception-type}'是预期 .
我试图解决但不是
这是web.xml中的代码
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
version="2.5"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/servlet-context.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value></param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
<filter-name>characterEncodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>characterEncodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<error-page>
<location>/error</location>
</error-page>
</web-app>
错误显示在 /error
之前的标签 location
上 .
我该怎么做才能解决日食错误?
1 回答
从中更改
web-app
元素至