如何解决从pickle.load（）函数使用时发生的错误？-Java 学习之路

我想在IPython环境中加载数据集并使用它 .

在包含数据集的目录中，我有这些文件：

batches.meta
data_batch_1
data_batch_2
data_batch_3
data_batch_4
data_batch_5
自述文件
test_batch

我写了这段代码：

import os
import pickle as pickle
import numpy as np
import matplotlib.pyplot as plt

#Function Definition
def load_CIFAR(ROOT):
xs=[];
ys=[];
for b in range(6):
    f = os.path.join(ROOT, "data_batch_%d"%(b+1));
    X, Y = load_CIFAR_batch(f);
    xs.append(X);
    ys.append(Y);
Xtr = np.concatenate(xs);
Ytr = np.concatenate(ys);

del X, Y;
Xte, Yte = load_CIFAR_batch(os.path.join(ROOT, "test_batch"));
return Xtr, Ytr, Xte, Yte

#Function Definition
def load_CIFAR_batch(filename):
with open(filename, 'r') as f:

    ****** Here is where  error occurs
    datadict = pickle.load(f);
    ******
    X = datadict['data'];
    Y = datadict['labels'];
    X = X.reshape(10000, 3, 32, 32).transpose(0,2,3,1).astype("float");
    Y = np.array(Y);
    return X, Y;

但是，当我使用此函数使用以下命令加载此数据集时，我遇到[需要一个类似字节的对象，而不是'str']错误 .

#The directory of my dataset in my hard drive
url = 'D:\\OTIWU\\data\\cifar10'
Xtr, Ytr, Xte, Yte = load_CIFAR(url)

上面是我用过的命令 .

The whole error:
---------------------------------------------------------------------------
TypeError  Traceback (most recent call last)
<ipython-input-14-f0576df4fbda> in <module>()
----> 1 Xtr, Ytr, Xte, Yte = load_CIFAR(url)

<ipython-input-10-fedf6bd7c144> in load_CIFAR(ROOT)
      4     for b in range(1,6):
      5         f=os.path.join(ROOT, "data_batch_%d" % (b, ));
      ----> 6         X, Y=load_CIFAR_batch(f);
      7         xs.append(X);
      8         ys.append(Y);

      <ipython-input-13-368cd3e9d8d2> in load_CIFAR_batch(filename)
      1 def load_CIFAR_batch(filename):
      2     with open(filename, 'r') as f:
      ----> 3         datadict = pickle.load(f);
      4 
      5         X = datadict['data'];

      TypeError: a bytes-like object is required, not 'str'

我该如何解决这个问题？

2 回答

0

我找到了解决方案 . 这是与python 3.x相关的问题 . 当我用python 2.x运行它时，我可以读取数据集中的所有数据 . 我还要说我已经改变了一点源代码 . 我的意思是我从cPickle库中使用而不是Pickle和除了这个问题之外的所有源代码都和以前一样 .

回复于 2024-04-20T02:27:42+08:00
0
您需要以二进制模式打开文件：
```
with open(filename, 'rb') as f:
```
回复于 2024-04-20T02:27:42+08:00

如何解决从pickle.load（）函数使用时发生的错误？

2 回答

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