Angular 2路由无法正常工作

我似乎无法使用Angular 2中的子项进行路由 . 该应用程序是我的第一个Angular 2应用程序，它非常简单，顶部有一个导航栏，可以填充页面下半部分的内容 . 每当我点击任何导航链接时，他们都导航到同一个孩子，甚至更糟糕的是那个孩子的内容堆叠，这意味着我点击一次，孩子加载到下面，我再次点击它再次加载下面，所以我有两次，等等 .

完整内容可在此处找到：plunker

这是我的searching.routing.ts文件：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

import { AdvancedSearchComponent } from './advanced-search/advanced-search.component';
import { GuidedSearchComponent } from './guided-search/guided-search.component';
import { QuickSearchComponent } from './quick-search/quick-search.component';

const searchesRoutes: Routes = [
    {
        children: [
            { path: 'advanced-search', component: AdvancedSearchComponent },
            { path: 'guided-search', component: GuidedSearchComponent },
            { path: 'quick-search', component: QuickSearchComponent }
        ],
        path: '',
        component: GuidedSearchComponent
    }
];

export const searchesRouting: ModuleWithProviders = RouterModule.forChild(searchesRoutes);

这是我的app.routing.ts文件：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

const searchesRoutes: Routes = [
    { path: 'searches', loadChildren: 'app/searches/searches.module#SearchesModule' },
    { path: '', redirectTo: "/searches", pathMatch: 'full' }
];

const appRoutes: Routes = [
    ...searchesRoutes
];

export const appRoutingProviders: any[] = [
];

export const routing: ModuleWithProviders = RouterModule.forRoot(appRoutes);

所以再次，这不能正常工作，但如果我在主文件中执行所有路由，如下所示：

import { ModuleWithProviders } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';

import { AdvancedSearchComponent } from './searches/advanced-search/advanced-search.component';
import { GuidedSearchComponent } from './searches/guided-search/guided-search.component';
import { QuickSearchComponent } from './searches/quick-search/quick-search.component';

const appRoutes: Routes = [
    { path: 'searches/advanced-search', component: AdvancedSearchComponent },
    { path: 'searches/guided-search', component: GuidedSearchComponent },
    { path: 'searches/quick-search', component: QuickSearchComponent },
    { path: '', redirectTo: "/searches/guided-search", pathMatch: 'full' }
];

export const appRoutingProviders: any[] = [
];

export const routing: ModuleWithProviders = RouterModule.forRoot(appRoutes);

但我想学习如何将搜索路径委托给子模块以使其更易于管理 .