我使用oracle apex来创建一个应用程序 .

有没有办法让表格单元格显示基于单元格内部的不同链接？

所以我希望有一个图标''链接到空单元格内的'创建'页面 .

这是apex的交互式报告 .

enter image description here

但我已将资产列设置为“编辑”页面的链接

enter image description here

以下是生成数据的代码：

select ID,
(SELECT distinct listagg(v.asset_id,', ') within group (order by s.id) from subnet_lookup l, infra_assets_master v where l.subnet_id = s.id AND l.link_id = v.id AND l.def_id = 3) as Assets,
(SELECT distinct listagg(v.hostname,', ') within group (order by s.id) from subnet_lookup l, infra_assets_master v where l.subnet_id = s.id AND l.link_id = v.id AND l.def_id = 3) as Hostname,
(SELECT distinct listagg(m.hostname,', ') within group (order by s.id) from subnet_lookup l, servers_master m where l.subnet_id = s.id AND l.link_id = m.id AND l.def_id = 1) as Servers,

from subnet s 
where NETWORK_ID = :P55_NETWORK_ID
ORDER BY ID desc

有没有办法我可以设置一个条件，根据单元格内的值显示不同链接的不同信息？

oracle oracle-apex