Firebase获取用户数据 - Swift-Java 学习之路

我想获取数据，我已经多次这样做了，但由于某种原因它不起作用，我认为没有理由为什么 .

我获取数据的代码

func fetchCurrentUserInfo() {

    let currentUser = Auth.auth().currentUser!
    let currentUserRef = dataBaseRef.child("users").child(currentUser.uid)

    currentUserRef.observeSingleEvent(of: .value, with: { (snapshot) in

        let user = UserClass(snapshot: snapshot)
        self.downloadImageFromFirebase(urlString: user.photoURL!)
        self.userName.text = user.getFullName()

        //SD Cache
        self.userProfileImage.sd_setImage(with: URL(string: user.photoURL!), placeholderImage: UIImage(named: "UserImageTemplate"))

    }) { (error) in
        let alert = SCLAlertView()
        _ = alert.showError("OOPS!", subTitle: error.localizedDescription)
    }
}

我的用户类文件

struct UserClass {

        var firstName: String?
        var email: String?
        var photoURL: String?
        var uid: String?
        var ref: DatabaseReference!
        var key: String?
        var lastName: String?
        var accountType: String?

        init(snapshot: DataSnapshot){

            key = snapshot.key
            ref = snapshot.ref
            accountType = (snapshot.value! as! NSDictionary)["Account Type"] as? String
            firstName = (snapshot.value! as! NSDictionary)["First Name"] as? String
            email = (snapshot.value! as! NSDictionary)["email"] as? String
            uid = (snapshot.value! as! NSDictionary)["uid"] as? String
            photoURL = (snapshot.value! as! NSDictionary)["photoURL"] as? String
            lastName = (snapshot.value! as! NSDictionary)["Last Name"] as? String
        }

        func getFullName() -> String {
            return ("\(firstName!) \(lastName!)")
        }

    }
}

我已将读取和写入规则设置为true . 当我调用fetchCurrentUserInfo函数时，它返回第一个名字，姓氏，密钥等的所有数据，但它返回照片URL，UID或电子邮件为nil给我错误：致命错误： unexpectedly found nil while unwrapping an Optional value .

1 回答

您的崩溃日志说明了一切 . 您正试图通过 as! 强制转换来展开可选变量 . 确保 snapshot 中包含有效值 .

此外，一个更好的模型会这样，这是更安全的：

struct UserClass {

        var firstName: String!
        var email: String!
        var photoURL: String!
        var uid: String!
        var ref: DatabaseReference!
        var key: String!
        var lastName: String!
        var accountType: String!

        init?(snapshot: DataSnapshot?) {

            guard let value = snapshot?.value as? [String: AnyObject],
                let accountType = value["Account Type"] as? String,
                let firstName = value["First Name"] as? String,
                let email = value["email"] as? String,
                let uid = value["uid"] as? String,
                let photoURL = value["photoURL"] as? String,
                let lastName = value["Last Name"] as? String else {
                    return nil
            }

            self.key = snapshot?.key
            self.ref = snapshot?.ref
            self.accountType = accountType
            self.firstName = firstName
            self.email = email
            self.uid = uid
            self.photoURL = photoURL
            self.lastName = lastName
        }

        func getFullName() -> String {
            return ("\(firstName!) \(lastName!)")
        }

    }

回复于 2024-04-29T07:24:26+08:00

Firebase获取用户数据 - Swift

1 回答

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