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在Django Class Based View中覆盖get（）以进行过滤

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我正在开始一个新的应用程序，我正在尽力接受基于类的视图 . 啊，成长的痛苦 . 我试图在这里从GET变量做一个简单的过滤器，如果它不存在我想返回由id desc排序的所有对象，如果是，我想过滤，排序并返回过滤后的列表 .

我写了30行代码来做这件事，所以我一定做错了，对吧？我尝试重写get_queryset（），现在我想起来了，也许我应该在get_queryset（）中调用self.request.GET ['search']来进行这种过滤 . 有没有一种标准的方法来实现这一目标？

class MyModelList(AdminPageMixin, ListView):
    model = MyModel
    context_object_name = 'object'
    template_name = 'template/list.html'

    def get(self, request, *args, **kwargs):
        if 'search' in request.GET and len(request.GET['search']):
            search = request.GET['search']
            self.object_list = MyModel.objects.filter(advertiser__name=search).orderby('-id')
            context = self.get_context_data(object_list=self.object_list, search=search)
        else:
            self.object_list = MyModel.objects.all()
            context = self.get_context_data(object_list=self.object_list).orderby('-id')
        return self.render_to_response(context)

    def get_context_data(self, **kwargs):
        context = super(MyModelList, self).get_context_data(**kwargs)
        form = MyModelForm
        try:
            context['search'] = kwargs['search']
        except KeyError:
            pass
        context['form'] = form
        context['form_action'] = reverse('mymodel-add')
        context['form_display'] = 'hide'
        context['form_save_label'] = 'Add'
        return context

其次，为了使问题复杂化，我有一个CreateView和一个UpdateView，我想分享我的ListView的get（）或get_queryset（）和get_context_data（）方法 . 我确信使用Mixin是可能的，但同样，我正在寻找一种标准化的方法 . 建议？这是CreateView，我想在其中共享ListView的方法 .

class MyModelAdd(AdminPageMixin, CreateView):
    model = MyModel
    form_class = MyModelForm
    context_object_name = 'object'
    template_name = 'templates/list.html'

    def get_success_url(self):
        return reverse('mymodel-list')

    def get_context_data(self, **kwargs):
        context = super(MyModelAdd, self).get_context_data(**kwargs)
        context['form_action'] = reverse('mymodel-add')
        context['form_display'] = 'show'
        context['object_list'] = MyModel.objects.all()
        return context

    def form_invalid(self, form):
        form = MyModelForm(self.request.POST)
        context = self.get_context_data()
        context['form'] = form
        context['form_action'] = reverse('mymodel-add')
        context['form_display'] = 'show'
        context['form_save_label'] = 'Add'
        return render(self.request, 'templates/list.html', context)
django django-class-based-views

2 回答

  • 3

    首先，你的观察是正确的：你绝对应该使用 get_queryset 来过滤列表 . 我建议采取以下措施：

    class MyModelList(AdminPageMixin, ListView):
    model = MyModel
    context_object_name = 'object'
    template_name = 'template/list.html'

    def get_queryset(self):
        qs = self.model.objects.all()
        search = self.request.GET.get('search')
        if search:
            qs = qs.filter(advertiser__name__icontains=search)
        qs = qs.order_by("-id") # you don't need this if you set up your ordering on the model
        return qs

    其次，如果你真的需要在List和其他视图之间重用代码，你最好编写一个单独的函数而不是使用mixin .

    附注：您的表单中不需要 form_action URL;只需设置 action="" ，它将POST到同一个URL .

    回复于
  • 0

    最好的方法是过滤'get_context_data'中的数据 .

    def get_context_data(self, **kwargs):
    context = super(MyModelAdd, self).get_context_data(**kwargs)
    context['form_action'] = reverse('mymodel-add')
    context['form_display'] = 'show'
    context['object_list'] = MyModel.objects.all(user=self.request.user)# that's will filter the user data
    return context
    回复于

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