我有两个表 Tbl_payroll_leave_employeev2
和 tbl_payroll_leave_schedulev2
,我想 join
他们但我得到这样的错误
SQLSTATE [23000]:完整性约束违规:1052列在where子句是不明确的 'payroll_leave_employee_id'(SQL:从tbl_payroll_leave_employee_v2内选择payroll_employee_id加入tbl_payroll_leave_schedulev2上tbl_payroll_leave_employee_v2.payroll_leave_employee_id = tbl_payroll_leave_schedulev2.payroll_leave_employee_id其中payroll_leave_employee_id = 5)◀
我的 table 结构
$employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id')
->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id')
->where('payroll_leave_employee_id',$emp)
->get();
1 回答
在where条件中,您必须定义表
tbl_payroll_leave_employee_v2
或表tbl_payroll_leave_schedulev2
的字段payroll_leave_employee_id