我使用Volley来注册用户的姓名,密码和电子邮件以进行注册 . 我从This tutorial参考了 . 并按照本教程中的定义进行操作 .
这是我的代码:
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST,
URL_string.api_url,null
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
Log.i("Result", "Success");
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.i("Result", "UnSuccess");
}
}){
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> params = new HashMap<String, String>();
Log.i("Result_Params",emailValue + passwordValue + nameValue);
params.put("email", emailValue);
params.put("password", passwordValue);
params.put("name", nameValue);
return super.getParams();
}
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
HashMap<String, String> headers = new HashMap<String, String>();
headers.put("Content-Type", "application/json; charset=utf-8");
return super.getHeaders();
}
};
RequestQueue requestQueue = Volley.newRequestQueue(this);
jsonObjectRequest.setRetryPolicy(new DefaultRetryPolicy(DefaultRetryPolicy.DEFAULT_TIMEOUT_MS * 2, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
requestQueue.add(jsonObjectRequest);
但是我的代码显示了这个错误:
[368] BasicNetwork.performRequest: Unexpected response code 422 for http://myapi.com/api/register
错误422在API上定义为:
{
"message": "422 Unprocessable Entity",
"errors": {
"email": [
"The email field is required."
],
"password": [
"The password field is required."
],
"name": [
"The password field is required."
]
},
"status_code": 422
}
我试过了:
-
将JsonObjectRequest更改为StringRequest,
-
在URL_string.api_url处的原始网址,
但反应仍然相同 . 这是因为我没有为Volley库做任何课程吗?我也从Androidhive.info那样做了,但失败了!
我现在不知道如何继续这一步,而登录getParams会记录用户输入的名称,电子邮件和密码的正确值,但仍然无法使用POST操作 . 请帮忙!提前致谢!
1 回答
您需要返回您创建的params对象,而不是返回父方法(为空) .
正如pablobu所指出的,这也适用于你的getHeaders():