这是我的index.html
<form action="submitForm" method="get"> <input type="submit" name="Submit" value="submit" onclick="" /> </form>
这是我的web.xml
`<servlet>
<servlet-name>submitForm</servlet-name>
<servlet-class>student.StudentSurveyFormSubmit</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>submitForm</servlet-name>
<url-pattern>/submitForm</url-pattern>
</servlet-mapping>`
还有我的servlet类
package student; @WebServlet("/StudentSurveyFormSubmit") public class StudentSurveyFormSubmit extends HttpServlet { protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("<h1>" + "Hi, "+request.getParameter("firstName") +" I am here" + "</h1>"); }}
每当我部署war文件并单击sumbot按钮时，我会得到一个异常：
服务器遇到内部错误（），导致无法完成此请求 .
例外
javax.servlet.ServletException：实例化servlet类student.StudentSurveyFormSubmit org.jboss.as.web.security.SecurityContextAssociationValve.invoke（SecurityContextAssociationValve.java:153）org.apache.catalina.valves.ErrorReportValve.invoke（ErrorReportValve.java:102 ）org.apache.catalina.connector.CoyoteAdapter.service（CoyoteAdapter.java:368）org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:877)org.apache.coyote.http11.Http11Protocol $ Http11ConnectionHandler.process （Http11Protocol.java:671)org.apache.tomcat.util.net.JIoEndpoint $ Worker.run（JIoEndpoint.java:930)java.lang.Thread.run（Unknown Source）
我哪里错了？
1 回答
如果使用
web.xml定义servlet，则删除@WebServlet注释，因为现在有2个不同的映射 .