在Laravel中获取MethodNotAllowedHttpException错误-Java 学习之路

我正在学习Laravel . 我正在尝试创建一个列出汽车表中汽车的表单，如果单击，则发送到另一个基于DB查询的表单，该查询返回所选汽车的数据（由$ modelesc标识） .

此表单将数据发送到“订单”表 . 使用我现在的代码，我无法在订单表上发布订单 . 它收到消息：“RouteCollection.php第233行中的MethodNotAllowedHttpException：”

这是代码

Web.php

Route::get('catalog', 'carController@catalog');
Route::get('orders/', 'CarController@orders')->name('orders');

CarController

function catalog() {
    $cars = DB::table('cars')->get();
    return view('catalog', compact('cars'));
}

function orders(Request $request) {
    $modelesc = $request->modelesc;
    $cars = DB::table('cars')->where('Model', $modelesc)->get();
    $colours = DB::table('colours')->get()->pluck('Colour');
    return view('orders', compact('cars', 'colours'));
}

Catalog.blade.php

@foreach($cars as $car)
{!! Form::open(array('action' => 'CarController@orders', 'method' => 'GET')) !!}
{!! Form::hidden('$modelesc', $car->Model) !!}
{!! Form::submit($car->Model) !!}
{!! Form::close() !!}   
@endforeach

Orders.blade.php

@foreach($cars as $car)
{!! Form::open(['method' => 'POST']) !!}
<a href="{{route('orders', $car->Model) }}">{{ $car->Model }}</a>
{!! Form::hidden('users_id', Auth::user()->id) !!}
{!! Form::hidden('Fabrication_date', date('Y-m-d')) !!}
{!! Form::select('Colour_id', $colours) !!}
{!! Form::hidden('Order_status_id', '1') !!}
{!! Form::submit('Ok') !!}
{!! Form::close() !!}
@endforeach

表订单具有以下结构：

$table->increments('id');
        $table->integer('users_id')->unsigned();
        $table->foreign('users_id')->references('id')->on('users')->onDelete('cascade')->onUpdate('cascade');
        $table->string('Model');
        $table->date('Fabrication_date');
        $table->integer('Colour_id')->unsigned();
        $table->foreign('Colour_id')->references('id')->on('colours')->onDelete('cascade')->onUpdate('cascade');
        $table->integer('Order_status_id')->unsigned();
        $table->foreign('Order_status_id')->references('id')->on('order_status')->onDelete('cascade')->onUpdate('cascade');
        $table->timestamps();

2 回答

更新您的订单功能

public function orders(Request $request) 
{
    $modelesc = $request->modelesc;
    $cars = DB::table('cars')->where('Model', $modelesc)->get();
    ...
}

Catalog.blade.php

Form::hidden('modelesc', $car->Model)

您的隐藏输入的 value 将由 request->modelesc 读取，您最终会得到一个类似于此 http://mysite.dev/orders?modelesc=toyota 的URL .

Some advice

您使用表单只提交隐藏的输入 . 没有用户输入 . 在我看来，使用简单的锚点更容易 <a></a> .

@foreach($cars as $car)
    <a href="/orders?{{ $car->Model }}">{{ $car->Model }}</a>
@endforeach

结果相同 .

使用漂亮的网址让它变得更好 . 更改路线定义

Route::get('orders/{modelesc}', 'CarController@orders')->name('orders');

和锚

<a href="/orders/{{ $car->Model }}">{{ $car->Model }}</a>

用命名路线

<a href="{{ route('orders', $car->Model) }}">{{ $car->Model }}</a>

而且功能

public function orders($modelesc) 
{
     $cars = DB::table('cars')->where('Model', $modelesc)->get();
     ...
}

回复于 2024-04-25T22:37:59+08:00

改变您的路线：

Route::get('orders/{model}', 'CarController@orders')->name('orders');

在此之后将您的控制器更改为：

public function orders($model) {
        $cars = DB::table('cars')->where('Model', $model)->get();
        if(!count($cars)){
            abort(404);
        }
        $colours = DB::table('colours')->get()->pluck('Colour');
        //$status = DB::select('select * from order_status where id = ?', [1])->get(); //this variable is never used
        return view('orders', compact('cars', 'colours'));
    }

现在更改Catalog.blade.php

在您的情况下，您不需要在您的订单页面中输入表单

@foreach($cars as $car)
  <a href="{{route('order', ['model' => $car->Model])}}">{{ $car->Model }}</a>
@endforeach

回复于 2024-04-25T22:37:59+08:00

在Laravel中获取MethodNotAllowedHttpException错误

2 回答

相关问题