使用Servlet的GWT FileUpload

1 回答

• 0

  我对我的代码做了一些更改：我更改了应用程序布局：我添加了一个TextArea，它显示了上传的txt文件的内容 . 现在这个非常简单的应用程序将txt文件上传到服务器，然后保存 . 然后服务器读取txt文件将内容发送到客户端并删除保存的文件 .

  主要变化：

  我给fileupload一个名字：

  public class GwtFileUploadDemo implements EntryPoint {
  
  private static final String UPLOAD_ACTION_URL = GWT.getModuleBaseURL() + "upload";
  
  private FormPanel form;
  private Label info;
  private FileUpload fileupload;
  private Button uploadFileBtn;
  private TextArea outputText;
  
  public void onModuleLoad() {
  
      init();
  
      uploadFileBtn.addClickHandler(new ClickHandler() {
          @Override
          public void onClick(ClickEvent event) {
              String filename = fileupload.getFilename();
  
              if(filename.length() == 0) {
                  Window.alert("File Upload failed");
              } else if(filename.endsWith(".txt")) {
  
                  form.submit();          
  
              } else {
                  Window.alert("File is not a txt file");
              }
          }
      });
  
  
      form.addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() {
          @Override
          public void onSubmitComplete(SubmitCompleteEvent event) {
  
              if(event.getResults().length() == 0) {
                  Window.alert("Something went wrong - Try again");
              } else {
                  outputText.setText(event.getResults());                 
              }
          }
      });
  
  
      VerticalPanel vp = new VerticalPanel();
      vp.add(info);
      vp.add(fileupload);
      vp.add(new HTML("<br>"));
      vp.add(uploadFileBtn);
      vp.add(outputText);
  
      form.add(vp);
      RootPanel rp = RootPanel.get();
      rp.add(form);
  }
  
  private void init() {
      form = new FormPanel();
      form.setAction(UPLOAD_ACTION_URL);
      form.setEncoding(FormPanel.ENCODING_MULTIPART);
      form.setMethod(FormPanel.METHOD_POST);
  
      info = new Label("Choose a txt file");
  
      fileupload = new FileUpload();
  
      //Here I added a name to the fileuploader
      fileupload.setName("uploader");
  
      uploadFileBtn = new Button("Show content of txt File");
  
      outputText = new TextArea();
      outputText.setEnabled(false);
  }
  }
  

  在服务器端的Servlet中，我添加了一个检查，如果解析的List是空的 . 我使用path，name和filePath创建文件 . 然后我用BufferedReader读取文件，然后在响应中写入上下文：

  public class FileUploadServlet extends HttpServlet
  {
  
  private static final long serialVersionUID = 1L;
  
  @Override
  protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {      
  
      System.out.println("Inside doPost");
  
      try {
          if (!ServletFileUpload.isMultipartContent(request)) {                                 
              throw new FileUploadException("error multipart request not found");              
          }       
  
          DiskFileItemFactory factory = new DiskFileItemFactory();            
  
          ServletFileUpload upload = new ServletFileUpload(factory);
  
          List<FileItem> items = upload.parseRequest(request);
  
          if (items == null) {            
              response.getWriter().write("File not correctly uploaded");
              return;
          }
  
          Iterator<FileItem> iter = items.iterator();
  
          while (iter.hasNext()) {
              FileItem item = iter.next();
              System.out.println("Start writing File");
  
              String uploadPath = ".";
              String fileName = new File(item.getName()).getName();
              String filePath = uploadPath + File.separator + fileName;
  
              System.out.println("File-Pfad:" + filePath);        
  
              File uploadedFile = new File(filePath);
              item.write(uploadedFile);               
  
              String content = "";  
  
              FileReader fileReader = new FileReader(filePath);
  
              BufferedReader bufferedReader = new BufferedReader(fileReader);
  
              String line = null;
  
              while((line = bufferedReader.readLine()) != null) {
                  content = content + line + "\n";
              }   
  
              bufferedReader.close();  
  
              PrintWriter out = response.getWriter();
              response.setHeader("Content-Type", "text/html");
              out.println(content);
              out.flush();
              out.close(); 
  
              uploadedFile.delete();
  
              System.out.println("Finished reading File");
          }
  
      } catch (Exception exc) {
          exc.printStackTrace();
          PrintWriter out = response.getWriter();
          response.setHeader("Content-Type", "text/html");
          out.println("Error");
          out.flush();
          out.close();
      }
      System.out.println("FileUploadServlet doPost end");
  }
  }
  

  我认为问题是我忘了给fileupload一个名字，因为在我添加了名字之后我测试了代码并且突然得到错误并写了我的文件 .

  回复于 2024-04-24T01:10:19+08:00