如何在Javascript中减去两个日期并将日期添加到特定日期

1 回答

• 0

  如果您在JavaScript中查看Date对象及其方法和属性，您会发现JavaScript自1970年以来的时间基于毫秒 .

  知道您可以通过添加或减去毫秒来轻松修改日期 .

  /**
   * subtractDateFromDate
   * Use the millisecond value insert both elements to calculate a new date.
   * @param d1 {Date}
   * @param d2 {Date}
   */
  function subtractDateFromDate(d1, d2) {
      return new Date(d1.getTime() - d2.getTime());
  }
  /**
   * addDaysToDate
   * Create a new Date based on the milliseconds of the first date,
   * adding the milliseconds for the extra days specified.
   * Notice that days can be a negative number.
   * @param d {Date}
   * @param days {number}
   */
  function addDaysToDate(d, days) {
      var oneDayInMilliseconds = 86400000;
      return new Date(d.getTime() + (oneDayInMilliseconds * days));
  }
  

  并在没有moment.js的情况下格式化日期：

  /**
   * formatDate
   * returns a string with date parameters replaced with the date objects corresponding values
   * @param d {Date}
   * @param format {string}
   */
  function formatDate(d, format) {
      if (format === void 0) { format = "!d!/!m!/!y!"; }
      return format
          .replace(/!y!/ig, d.getFullYear().toString())
          .replace(/!m!/ig, (d.getMonth() + 1).toString())
          .replace(/!d!/ig, d.getDate().toString());
  }
  //Testing
  var d = new Date();
  console.log("d/m/y:", formatDate(d, "!d!/!m!/!y!"));
  console.log("m/d/y:", formatDate(d, "!m!/!d!/!y!"));
  console.log("It was the d of m, y:", formatDate(d, "It was the !d! of !m!, !y!"));
  

  回复于 2024-04-19T23:42:06+08:00