如何在给定日期（PHP）之后计算经常性周期的最近日期

6 回答

• 4

  您可以使用DatePeriod来完成它：

  $begin = new DateTime('2016-01-01');
  $end = new DateTime('2016-12-31');
  $interval = new DateInterval('P14D');
  $datePeriod = new DatePeriod($begin, $interval ,$end);
  
  $givenDate = new DateTime('2016-01-17');
  
  foreach ($datePeriod as $date) {
      if ($date < $givenDate) {
          continue;
      }
  
      echo 'The next recurring period date is ' . $date->format('Y-m-d');
      break;
  }
  

  输出将是：

  下一个经常性的日期是2016-01-29

  回复于 2024-05-04T13:58:37+08:00
• 0

  如果你是开放的，不介意数据库选项和迷你cron脚本，我有一个建议 . 创建一个名为recurring_track的表，并具有键值列：

  例如：

  last_recurring_period作为键和值为05-25-2016

  现在运行一个cron脚本，只在每次重复出现持续时间时更新它 .

  现在，您只需要查询此表以确定最后一个周期时间，以及现在何时将是您可以添加和确定的给定日期的下一个周期 .

  回复于 2024-05-04T13:58:37+08:00
• 0

  试试这个，

  $starting_dat = '2016-01-01';
      $recurring_prd = "2 week";
      $given_dat = '2016-02-28';
  
      while ($given_dat > $starting_dat)
      {
  
  
              $next_date=date('Y-m-d', strtotime($recurring_prd, strtotime(date($starting_dat))));
              $starting_dat = $next_date;
      }
  
      echo date('d-m-Y', strtotime($next_date));
  

  回复于 2024-05-04T13:58:37+08:00
• 0

  $now = time(); // or your date as well
   $your_date = strtotime("2010-01-01");
  
   //Get difference in days  
   $datediff = $now - $your_date; // in days say 60 days 
  
   //use mod with your reoccurring period 
   $remain = $datediff % $recPeriod // her say 2 weeks = 14 days recurring gets you 4
   //nearest recured date 
   $recdate = strtotime("-".$remain." day", $now); // 4 days ago 
  
  Modify similar way for next date too
  

  回复于 2024-05-04T13:58:37+08:00
• 0

  而不是循环，你可以只做一些数学并利用DateTime类：

  $start = new DateTime("2016-01-01");
  $interval = 14;
  
  $current = new DateTime("2016-01-17");
  
  // Here we subtract from the interval (14 days) the amount of days remaining
  // to the next recurring date
  $daysUntilNext = $interval - ($current->diff($start)->days % $interval);
  
  $next = $current->modify("+$daysUntilNext days");
  
  // $next now contains the next recurring date
  

  回复于 2024-05-04T13:58:37+08:00
• 0

  另一种看法，与@Matei Mihai的相似，但不需要在最后一个循环中进行检查 . 感觉应该有一个更好的方法来添加DateInterval的多个实例到DateTime .

  <?php
  $start   = new DateTime('2016-01-01');
  $cutOff  = new DateTime('2016-01-17');
  $period  = new DateInterval('P2W');
  
  // Find out the total number of complete periods between the two dates
  $distance = $start->diff($cutOff)->days;
  $periodsBetween = (int) ($distance / $period->d);
  
  // Then add on that number of periods + 1 to the original date
  for ($a=1; $a<=$periodsBetween + 1; $a++)
  {
      $start->add($period);
  }
  
  echo $start->format('Y-m-d'); // 2016-01-29
  

  回复于 2024-05-04T13:58:37+08:00