Mock Laravel Eloquent模型 - 如何使用Mockery设置公共 property

8 回答

• 1

  如果要使用此值获取此属性，只需使用它：

  $mock ->shouldReceive('getAttribute')
      ->with('role')
      ->andReturn(2);
  

  如果你打电话 $user->role 你会得到 - 2 （ $user - 它的 User 模拟类）

  回复于 2024-04-27T20:37:40+08:00
• 2

  这个答案有点晚，但希望它会帮助某人 . 您当前可以使用'alias'关键字在模拟的Eloquent对象上设置静态属性：

  $mocked_model = Mockery::mock('alias:Namespace\For\Model');
  $mocked_model->foo = 'bar';
  $this->assertEquals('bar', $mocked_model->foo);
  

  这对于模拟外部供应商类（如某些Stripe对象）也很有帮助 .

  了解'alias'和'overload'关键字：http://docs.mockery.io/en/latest/reference/startup_methods.html

  回复于 2024-04-27T20:37:40+08:00
• 12

  要回答你的问题，你也可以尝试这样的事情：

  $mock = Mockery::mock('User');
  $mock->shouldReceive('hasRole')->once()->andReturn(true); //works fine
  $mock->shouldReceive('setAttribute')->passthru();
  $mock->roles = 2; 
  
  $mock->shouldReceive('getAttribute')->passthru();
  $this->assertEquals(2, $mock->roles);
  

  或者，如seblaze所示，使用部分模拟：

  $mock = Mockery::mock('User[hasRole]');
  $mock->shouldReceive('hasRole')->once()->andReturn(true);
  $mock->roles = 2; 
  $this->assertEquals(2, $mock->roles);
  

  但是，从你的代码片段来看，如果你正在编写单元测试，那么每个测试应该只做一个断言：

  function test_someFunctionWhichCallsHasRole_CallsHasRole() {
      $mock = Mockery::mock('User');
      $mock->shouldReceive('hasRole')->once();
  
      $mock->someFunctionWhichCallsHasRole();
  }
  
  function test_someFunctionWhichCallsHasRole_hasRoleReturnsTrue_ReturnsTrue() {
      $mock = Mockery::mock('User');
      $mock->shouldReceive('hasRole')->once()->andReturn(true);
  
      $result = $mock->someFunctionWhichCallsHasRole();
  
      $this->assertTrue($result);
  }
  

  回复于 2024-04-27T20:37:40+08:00
• 0

  Spy 是你的朋友：

  $mock = Mockery::spy('User');
  $mock->shouldReceive('hasRole')->once()->andReturn(true);
  $mock->roles = 2;
  $this->assertTrue(someTest($mock));
  

  回复于 2024-04-27T20:37:40+08:00
• -2

  试过这个？它应该涵盖你的问题 .

  https://github.com/padraic/mockery/blob/master/docs/11-MOCKING-PUBLIC-PROPERTIES.md

  我会说实施这些

  protected $roles = array();
  
  public function setRoles($roles)
  {
      $this->roles = $roles;
  }
  
  public function addRole($role)
  {
      $this->roles[] = $role;
  }
  

  然后你可以测试使用：

  $mock = Mockery::mock('User');
  $mock->shouldReceive('hasRole')->once()->andReturn(true);
  $mock->addRole(2);
  $this->assertTrue(someTest($mock));
  

  这个apse让你有机会在你执行一个getRoles（）时承诺一个格式，如果你做SOLID OOP就是Role对象的数组，或者你更喜欢使用数组，那么至少你知道它总是你得到的数组 .

  回复于 2024-04-27T20:37:40+08:00
• 0

  你有没有试过partial mocks？您可以尝试类似（未测试）的内容：

  $mock = Mockery::mock('User[hasRole]');
  $mock->shouldReceive('hasRole')->once()->andReturn(true);
  $mock->roles = 2; 
  $this->assertTrue(someTest($mock));
  

  回复于 2024-04-27T20:37:40+08:00
• 5

  Laravel 5.3中的部分模拟

  $mock = Mockery::mock(App\User::class)->makePartial();
  $mock->shouldReceive('hasRole')->once()->andReturn(true);
  $mock->roles = 2; 
  $this->assertEquals(2, $mock->roles);
  

  回复于 2024-04-27T20:37:40+08:00
• 0

  在这种情况下你可以使用stdclass .

  $obj = new stdClass();
  $obj->roles = 2;
  $mock = Mockery::mock('User');
  // return stdclass here.
  $mock->shouldReceive('hasRole')->once()->andReturn($obj);
  $mock->roles = 2;
  $this->assertEquals(2, $mock->roles);
  

  回复于 2024-04-27T20:37:40+08:00