在特定日期重复UILocalNotification-Java 学习之路

我需要设置UILocalNotification，我只需要从DatePicker获取小时和分钟，并需要设置特定日期（如：星期一）并在每个星期一重复 .

我有两个问题：

第一 ;是否可以在日期选择器的日期部分仅显示“日期名称”，如“星期日”？

第二个问题是;如果我想设置本地通知的具体日期，那么正确的代码是什么？

谢谢你的答案，下面是我的代码;

-(IBAction) alarmButton:(id)sender {

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init];
dateFormatter.timeZone = [NSTimeZone defaultTimeZone];
dateFormatter.timeStyle = NSDateFormatterShortStyle;
dateFormatter.dateStyle = NSDateFormatterShortStyle;

NSString *dateTimeString = [dateFormatter stringFromDate: dateTimePickerSet1.date];
NSLog ( @"Alarm Set :%@" , dateTimeString);

[self scheduleLocalNotificationWithDate1: dateTimePickerSet1.date];

}

-(void)scheduleLocalNotificationWithDate1:(NSDate *)fireDate {
UILocalNotification *notification = [[UILocalNotification alloc] init];

notification.fireDate = fireDate;
notification.alertBody = @"Alarm Set !";

[[UIApplication sharedApplication] scheduleLocalNotification:notification];

5 回答

Question 1 => 我无法理解你想要什么 . （但是如果你只想显示像 sunday, monday,....to saturday 这样的天的名字，那就用UIPickerView.）

Question 2 => YES 您可以获得特定日期的正确日期，您可以通过设置 localNotification.repeatInterval = NSWeekCalendarUnit; 获取每个特定日期的通知

为了实现它，还需要使用下面的（方法）代码 . 此方法将返回特定选定日期的正确日期，您只需要传递 day 作为方法的参数，如，

如果选定日是星期日，则通过1如果选择日是星期一，则通过2 . . . 如果选定的一天是星期六，那么通过7

这是方法代码：

-(NSDate *) getDateOfSpecificDay:(NSInteger ) day /// here day will be 1 or 2.. or 7
{
  NSInteger desiredWeekday = day
  NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSWeekdayCalendarUnit];
  NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1;

  NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:[NSDate date]];
  NSInteger currentWeekday = dateComponents.weekday;
  NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek;
  NSDateComponents *daysComponents = [[NSDateComponents alloc] init];
  daysComponents.day = differenceDays;
  NSDate *resultDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:[NSDate date] options:0];
  return resultDate;
}

别忘了设置 localNotification.repeatInterval = NSWeekCalendarUnit;

回复于 2024-05-03T22:31:57+08:00

这是@ iPatel的解决方案，它也会影响通过datepicker传入的时间组件 . （我还更新了他的解决方案，以使用未弃用的最新日历单元） .

- (NSDate *) getFireDateForDayOfWeek:(NSInteger)desiredWeekday withTime:(NSDate *)time // 1:Sunday - 7:Saturday
{
    NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSCalendarUnitWeekday];
    NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1;

    NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitWeekday fromDate:[NSDate date]];
    NSInteger currentWeekday = dateComponents.weekday;
    NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek;

    NSDateComponents *daysComponents = [[NSDateComponents alloc] init];
    daysComponents.day = differenceDays;
    NSDate *fireDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:[NSDate date] options:0];

    NSDateComponents *timeComponents = [[NSCalendar currentCalendar] components:     NSCalendarUnitHour | NSCalendarUnitMinute fromDate:time];
    NSDateComponents *fireDateComponents = [[NSCalendar currentCalendar]
                components: NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond
                fromDate:fireDate];

    fireDateComponents.hour = timeComponents.hour;
    fireDateComponents.minute = timeComponents.minute;
    fireDateComponents.second = 0;

    NSDate *resultDate = [[NSCalendar currentCalendar] dateFromComponents:fireDateComponents];

    // The day could be today but time is in past. If so, move ahead to next week
    if(resultDate.timeIntervalSinceNow < 0) {
        resultDate = [resultDate dateByAddingTimeInterval:60 * 60 * 24 * 7];
    }

    return resultDate;
}

回复于 2024-05-03T22:31:57+08:00

这个解决方案也需要时间，但它比Oren的简化得多

-(NSDate *) dateOfSpecificDay:(NSInteger ) day withFireTime:(NSDate *)timeDate/// here day will be 1 or 2.. or 7 and timeDate the current day with the desired time 
{
    NSInteger desiredWeekday = day;
    NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSCalendarUnitWeekday];
    NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1;

    NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitWeekday fromDate:[NSDate date]];
    NSInteger currentWeekday = dateComponents.weekday;
    NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek;
    if (differenceDays == 0) {
        //Check if should register for same day or for next week
        if ([timeDate compare:[NSDate date]] == NSOrderedAscending) {
            //Should schedule for next week
            differenceDays = daysInWeek;
        }
    }

    NSDateComponents *daysComponents = [[NSDateComponents alloc] init];
    daysComponents.day = differenceDays;
    NSDate *resultDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:timeDate options:0];

    return resultDate;
}

回复于 2024-05-03T22:31:57+08:00

这是 swift 版本：

func calculateTheNExtFriday(inputTime: NSDate) -> NSDate {
    let desiredWeekday = 6 // Friday

    let weekDateRange = NSCalendar.currentCalendar().maximumRangeOfUnit(NSCalendarUnit.Weekday)
    let daysInWeek = weekDateRange.length - weekDateRange.location + 1;

    let currentWeekday = NSCalendar.currentCalendar().components(NSCalendarUnit.Weekday, fromDate: inputTime).weekday
    let differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek

    let dateComponents = NSDateComponents()
    dateComponents.day = differenceDays

    let calculatedFridayDate = NSCalendar.currentCalendar().dateByAddingComponents(dateComponents, toDate: inputTime, options: NSCalendarOptions.init(rawValue: 0))
    return calculatedFridayDate!
}

在这个例子中，我在函数内部使用了desiredWeekday，但你也可以使用它作为参数 .

注意：请记住，第1天对应于星期日，2 - >星期一，依此类推

回复于 2024-05-03T22:31:57+08:00

斯威夫特3：

func calculateSpecificDay(_ desiredWeekday: NSInteger, fromDate: Date = Date()) -> Date {

    let weekDateRange = NSCalendar.current.maximumRange(of: .weekday)!
    let daysInWeek = weekDateRange.lowerBound.distance(to: weekDateRange.upperBound) - weekDateRange.lowerBound + 1

    let currentWeekday = NSCalendar.current.dateComponents([.weekday], from: fromDate).weekday
    let differenceDays = (desiredWeekday - currentWeekday! + daysInWeek) % daysInWeek

    var dateComponents = DateComponents()
    dateComponents.day = differenceDays

    let calculatedFridayDate = NSCalendar.current.date(byAdding: dateComponents, to: fromDate)
    return calculatedFridayDate!
}

如果选定日是星期日，则通过1
如果选择的日期是星期一，那么通过2
.
.
.
如果选定的一天是星期六，那么通过7

回复于 2024-05-03T22:31:57+08:00

在特定日期重复UILocalNotification

5 回答

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