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Python文本冒险游戏无法正常工作

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我似乎已经解决了这个问题 . 我前几天进入Python，所以如果这很容易，那就是原因 . ``
`def firstChoice():
time.sleep(2)
print('You come across a path, it splits at the end.')
time.sleep(1)
choice=input('Which path do you take, the left path (1) or the right path (2)? \n')
checkChoice()

def checkChoice():

correct

if choice=='1' or choice=='2':
    correct_choice=randint(1,2)
    if choice==correct_choice:
        correct=True
if choice!='1' or choice!='2':
    print('You decide to not take a path, and you die due to random circumstances.')
    time.sleep(1)
    print('Take a path next time, or at least take it correctly.')
    failScreen()

I've imported everything necessary (time and random) EDIT: Here's the whole code.`

import random
import time

choice=0

def introDisplay():
    print('This is the pre-game story.')
    time.sleep(1)
    print('It lasts for 5 lines.')
    time.sleep(1)
    print('When you can be arsed, fix this.')
    time.sleep(1)
    print('Thanks,')
    time.sleep(1)
    print('You, from 18/3/17')
    print()
    firstChoice()

def firstChoice():
    time.sleep(2)
    print('You come across a path, it splits at the end.')
    time.sleep(1)
    choice=input('Which path do you take, the left path (1) or the right path (2)? \n')
    checkChoice(choice)

def checkChoice(choice):
    correct=False
    if choice=='1' or choice=='2':
        correct_choice=random.randint(1,2)
        if choice==correct_choice:
            correct=True
    if choice!='1' and choice!='2':
        print('You decide to not take a path, and you die due to random circumstances.')
        time.sleep(1)
        print('Take a path next time, or at least take it correctly.')
        failScreen()




def failScreen():
    restart=True
    print('You have failed.')
    print('Do you want to retry?')
    restart1=input('Y or y = Yes. N or n = No. \n')
    if restart1=='y' or restart1=='Y':
        restart=True
    if restart1=='n' or restart1=='N':
        restart=False
    if restart1!='n' or restart!='N' or restart!='y' or restart!='Y':
        failScreen()
    if restart==True:
        introDisplay()
    if restart==False:
        exit()

introDisplay()
python

2 回答

  • 0

    首先，如果你正在使用python2.7你需要知道input（）如果你通过控制台给它一个数字，这个函数转换为int，那么你需要检查值，如果 choice == 1 或只是改变输入到 raw_input() （这是最好的方法），同样在 if choice!='1' and choice!='2': 你需要放 else: 然后你避免了很多检查或意外的值 .

    如果您使用的是python3，则raw_input是新的输入函数，因此您无需更改它

    并且，如果您想使用raw_input（）或者您正在使用python3，则需要将随机函数更改为 random.choice('1','2') ，因为您要将str与int进行比较，这里您的代码中包含python2.7的更改：

    import random
import time

choice=0

def introDisplay():
    print('This is the pre-game story.')
    time.sleep(1)
    print('It lasts for 5 lines.')
    time.sleep(1)
    print('When you can be arsed, fix this.')
    time.sleep(1)
    print('Thanks,')
    time.sleep(1)
    print('You, from 18/3/17')
    print()
    firstChoice()

def firstChoice():
    time.sleep(2)
    print('You come across a path, it splits at the end.')
    time.sleep(1)
    choice=raw_input('Which path do you take, the left path (1) or the right path (2)? \n')
    checkChoice(choice)

def checkChoice(choice):
    correct=False
    if choice=='1' or choice=='2':
        correct_choice=random.choice(['1','2'])
        if choice==correct_choice:
            correct=True
            print('You chose the correct path')
        else:
            print('You dont chose the correct path')
    else:
        print('You decide to not take a path, and you die due to random circumstances.')
        time.sleep(1)
        print('Take a path next time, or at least take it correctly.')
        failScreen()




def failScreen():
    restart=True
    print('You have failed.')
    print('Do you want to retry?')
    restart1=input('Y or y = Yes. N or n = No. \n')
    if restart1=='y' or restart1=='Y':
        restart=True
    if restart1=='n' or restart1=='N':
        restart=False
    if restart1!='n' or restart!='N' or restart!='y' or restart!='Y':
        failScreen()
    if restart==True:
        introDisplay()
    if restart==False:
        exit()

introDisplay()
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  • 0

    我猜你总是在 failScreen 结束，因为你的第二个 if 语句正在使用 !=1 or !=2 ，这将导致始终 true ...将其更改为 and 以查看它是否有帮助 .

    我也不确定 checkChoice 函数中是否可以看到 choice . 在Java中，您需要在function-bodys之外声明变量

    回复于

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