如何在web.xml中注册Spring @Configuration带注释的类而不是applicationContext.xml文件？

2 回答

• 11

  在 web.xml 中，您需要使用 AnnotationConfigWebApplicationContext 引导上下文：

  <servlet>
      <servlet-name>appServlet</servlet-name>
      <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
      <init-param>
          <param-name>contextClass</param-name>
          <param-value>
              org.springframework.web.context.support.AnnotationConfigWebApplicationContext
          </param-value>
      </init-param>
      <init-param>
          <param-name>contextConfigLocation</param-name>
          <param-value>
              org.package.YouConfigurationAnnotatedClass
          </param-value>
      </init-param>
  </servlet>
  

  并且不要忘记使用 @EnableWebMvc 来启动MVC注释 .

  进一步阅读：

  • Spring 3.1 MVC Enhancements

  • Spring 3.1 MVC Namespace Enhancements And Configuration

  编辑为“评论跟进”=>图灵完成：

  是的，你当然需要一个听众 . 虽然上面完全回答了“如何在web.xml中注册Spring @Configuration注释类而不是applicationContext.xml文件”的问题，但这里是一个来自Spring官方文档的example，它布局了完整的 web.xml ：

  <web-app>
    <!-- Configure ContextLoaderListener to use AnnotationConfigWebApplicationContext
         instead of the default XmlWebApplicationContext -->
    <context-param>
        <param-name>contextClass</param-name>
        <param-value>
            org.springframework.web.context.support.AnnotationConfigWebApplicationContext
        </param-value>
    </context-param>
  
    <!-- Configuration locations must consist of one or more comma- or space-delimited
         fully-qualified @Configuration classes. Fully-qualified packages may also be
         specified for component-scanning -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>com.acme.AppConfig</param-value>
    </context-param>
  
    <!-- Bootstrap the root application context as usual using ContextLoaderListener -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
  
    <!-- Declare a Spring MVC DispatcherServlet as usual -->
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <!-- Configure DispatcherServlet to use AnnotationConfigWebApplicationContext
             instead of the default XmlWebApplicationContext -->
        <init-param>
            <param-name>contextClass</param-name>
            <param-value>
                org.springframework.web.context.support.AnnotationConfigWebApplicationContext
            </param-value>
        </init-param>
        <!-- Again, config locations must consist of one or more comma- or space-delimited
             and fully-qualified @Configuration classes -->
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>com.acme.web.MvcConfig</param-value>
        </init-param>
    </servlet>
  
    <!-- map all requests for /app/* to the dispatcher servlet -->
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/app/*</url-pattern>
    </servlet-mapping>
  </web-app>
  

  回复于 2024-04-25T15:50:00+08:00
• 129

  在这里提出一个老问题，但是最近的Spring版本（v3.0）现在你可以完全摆脱web.xml，只要你在支持Servlet 3.0的web容器上部署你的应用程序 .

  可以实现Spring的WebApplicationInitializer接口来执行与web.xml中相同的配置 . 在Servlet 3.0容器上运行的Spring 3.0应用程序将自动检测此实现类 .

  如果设置相当简单，您可以使用Spring提供的另一个类，如下所示 . 这里所做的就是设置@Configuration类并列出servlet映射 . 保持设置非常简单 .

  public class WebInit extends AbstractAnnotationConfigDispatcherServletInitializer{
  
      @Override
      protected Class<?>[] getRootConfigClasses() {
          return null;
      }
  
      @Override
      protected Class<?>[] getServletConfigClasses() {
  
          return new Class[] {AppConfig.class};
      }
  
      @Override
      protected String[] getServletMappings() {
          return new String[] {
                   "*.html"
                  ,"*.json"
                  ,"*.do"};
      }
  }
  

  回复于 2024-04-25T15:50:00+08:00