我注意到,如果我使用函数调用map(),我在DataFrame上使用Window函数后,Spark会返回“Task not serializable”Exception这是我的代码:
val hc:org.apache.spark.sql.hive.HiveContext = new org.apache.spark.sql.hive.HiveContext(sc)
import hc.implicits._
import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions._
def f():String = "test"
case class P(name:String,surname:String)
val lag_result:org.apache.spark.sql.Column = lag($"name",1).over(Window.partitionBy($"surname"))
val lista:List[P] = List(P("N1","S1"),P("N2","S2"),P("N2","S2"))
val data_frame:org.apache.spark.sql.DataFrame = hc.createDataFrame(sc.parallelize(lista))
df.withColumn("lag_result", lag_result).map(x => f)
//df.withColumn("lag_result", lag_result).map{case x => def f():String = "test";f}.collect // This works
这是堆栈跟踪:
org.apache.spark.SparkException:在org.apache.spark.util.ClosureCleaner $ .ensureSerializable(ClosureCleaner.scala:304)org.apache.spark.util.ClosureCleaner $ .org $ apache $ spark $中无法序列化的任务util $ ClosureCleaner $$ clean(ClosureCleaner.scala:294)atg.apache.spark.util.ClosureCleaner $ .clean(ClosureCleaner.scala:122)at org.apache.spark.SparkContext.clean(SparkContext.scala:2055) at org.apache.spark.rdd.RDD $$ anonfun $ map $ 1.apply(RDD.scala:324)at org.apache.spark.rdd.RDD $$ anonfun $ map $ 1.apply(RDD.scala:323) at ...和更多引起:java.io.NotSerializableException:org.apache.spark.sql.Column序列化堆栈: - 对象不可序列化(类:org.apache.spark.sql.Column,值:'lag(name) ,1,null)windowspecdefinition(surname,UnspecifiedFrame)) - 字段(类:$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $ $ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC $$ iwC,name:lag_result,type:class org.apache . spark.sql.Column)......等等
1 回答
lag
返回o.a.s.sql.Column
,这是不可序列化的 . 同样的事适用于WindowSpec
. 在交互模式下,这些对象可以作为map
的闭包的一部分包含在内:一个简单的解决方案是将两者标记为瞬态: