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sed用一个单词替换行的范围

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我尽我所能得到这个，运气不好，我有以下文件，我想先替换 “<Connector port="8080"” xml block with ‘xxxx’

之前：

<!-- A "Connector" represents an endpoint by which requests are received
     and responses are returned. Documentation at :
     Java HTTP Connector: /docs/config/http.html (blocking & non-blocking)
     Java AJP  Connector: /docs/config/ajp.html
     APR (HTTP/AJP) Connector: /docs/apr.html
     Define a non-SSL HTTP/1.1 Connector on port 8080
-->
<Connector port="8080" protocol="HTTP/1.1" 
           connectionTimeout="20000" 
           redirectPort="8443" />
<!-- A "Connector" using the shared thread pool-->
<!--
<Connector executor="tomcatThreadPool"
           port="8080" protocol="HTTP/1.1" 
           connectionTimeout="20000" 
           redirectPort="8443" />
-->

之后：

<!-- A "Connector" represents an endpoint by which requests are received
     and responses are returned. Documentation at :
     Java HTTP Connector: /docs/config/http.html (blocking & non-blocking)
     Java AJP  Connector: /docs/config/ajp.html
     APR (HTTP/AJP) Connector: /docs/apr.html
     Define a non-SSL HTTP/1.1 Connector on port 8080
-->
xxxx
<!-- A "Connector" using the shared thread pool-->
<!--
<Connector executor="tomcatThreadPool"
           port="8080" protocol="HTTP/1.1" 
           connectionTimeout="20000" 
           redirectPort="8443" />
-->

我使用以下sed命令打印匹配的字符串：

sed -n '/<Connector port="8080"/,/>/p' filename

但是我无法开发它以获得高于输出 .

regex replace sed

3 回答

  • 0
    sed  '/<Connector port="8080"/,/>/ {
   N
   />/ s/.*/xxxx/
  }' YourFile

    在将连接器部分更改为xxxx之前加载连接器部分，这允许您最终对其进行测试（但如果没有，则不会比pobrelkey更好）

    回复于
  • 0

    这个 sed 应该对您的示例输入进行操作（但如果您有多个 <Connector port="8080" 部分，则会过于热心）：

    sed '/<Connector port="8080"/,/>/{ s/<Connector.*/xxxx/; t; d  }'

    但是处理这个问题需要一个XML解析器 . 例：

    #!/usr/bin/env ruby
require 'rexml/document'
include REXML
d = Document.new(File.read(ARGV[0]))
e = d.get_elements('//Connector[@port="8080"]').first
if !e.nil?
    e.parent.insert_after(e, Text.new('xxxx'))
    e.parent.delete(e)
end
File.open(ARGV[0],'w'){|f| f.print(d) }
    回复于
  • 2

    感谢所有的答案，他们运作良好 . 赞成它：我也从我的一个firend跟随也使用awk回答这个问题

    awk '/<Connector port/ {
print "abc"
getline
do {
 getline
} while (index($0, ">") == 0)
getline
} 
// { print $0}' < 1.txt
    回复于

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