如何获取MySQL数据库表的大小？-Java 学习之路

681

我可以运行此查询来获取MySQL数据库中所有表的大小：

show table status from myDatabaseName;

我想在理解结果方面提供一些帮助 . 我正在寻找最大尺寸的 table .

我应该看哪一栏？

15 回答

最后计算数据库的总大小：

(SELECT 
  table_name AS `Table`, 
  round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB` 
  FROM information_schema.TABLES 
  WHERE table_schema = "$DB_NAME"
)
UNION ALL
(SELECT 
  'TOTAL:',
  SUM(round(((data_length + index_length) / 1024 / 1024), 2) )
  FROM information_schema.TABLES 
  WHERE table_schema = "$DB_NAME"
)

回复于 2024-04-17T05:45:43+08:00

SELECT TABLE_NAME AS "Table Name", 
table_rows AS "Quant of Rows", ROUND( (
data_length + index_length
) /1024, 2 ) AS "Total Size Kb"
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'YOUR SCHEMA NAME/DATABASE NAME HERE'
LIMIT 0 , 30

您可以从“ information_schema ” - > SCHEMATA table - >“ SCHEMA_NAME ”列获取模式名称

Additional 您可以按照以下方式获得 size of the mysql databases .

SELECT table_schema "DB Name", 
Round(Sum(data_length + index_length) / 1024 / 1024, 1) "DB Size in MB" 
FROM   information_schema.tables 
GROUP  BY table_schema;

Result

DB Name              |      DB Size in MB

mydatabase_wrdp             39.1
information_schema          0.0

你可以get additional details in here.

回复于 2024-04-17T05:45:43+08:00

如果要查询使用当前选定的数据库 . 只需复制粘贴此查询即可 . （无需修改）

SELECT table_name ,
  round(((data_length + index_length) / 1024 / 1024), 2) as SIZE_MB
FROM information_schema.TABLES
WHERE table_schema = DATABASE() ORDER BY SIZE_MB DESC;

回复于 2024-04-17T05:45:43+08:00

1

这应该在mysql中测试，而不是postgresql SELECT table_schema, # "DB Name", Round(Sum(data_length + index_length) / 1024 / 1024, 1) # "DB Size in MB" FROM information_schema.tables GROUP BY table_schema;

回复于 2024-04-17T05:45:43+08:00

您可以使用此查询来显示表的大小（尽管您需要先替换变量）：

SELECT 
    table_name AS `Table`, 
    round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB` 
FROM information_schema.TABLES 
WHERE table_schema = "$DB_NAME"
    AND table_name = "$TABLE_NAME";

或者此查询列出每个数据库中每个表的大小，最大的第一个：

SELECT 
     table_schema as `Database`, 
     table_name AS `Table`, 
     round(((data_length + index_length) / 1024 / 1024), 2) `Size in MB` 
FROM information_schema.TABLES 
ORDER BY (data_length + index_length) DESC;

回复于 2024-04-17T05:45:43+08:00

假设您的数据库名称是 "news_alert". 然后此查询将显示数据库中所有表的大小 .

Size of all tables:

SELECT
  TABLE_NAME AS `Table`,
  ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)`
FROM
  information_schema.TABLES
WHERE
  TABLE_SCHEMA = "news_alert"
ORDER BY
  (DATA_LENGTH + INDEX_LENGTH)
DESC;

Output:

+---------+-----------+
    | Table   | Size (MB) |
    +---------+-----------+
    | news    |      0.08 |
    | keyword |      0.02 |
    +---------+-----------+
    2 rows in set (0.00 sec)

For specific table:

SELECT
  TABLE_NAME AS `Table`,
  ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024),2) AS `Size (MB)`
FROM
  information_schema.TABLES
WHERE
    TABLE_SCHEMA = "news_alert"
  AND
    TABLE_NAME = "news"
ORDER BY
  (DATA_LENGTH + INDEX_LENGTH)
DESC;

Output:

+-------+-----------+
| Table | Size (MB) |
+-------+-----------+
| news  |      0.08 |
+-------+-----------+
1 row in set (0.00 sec)

回复于 2024-04-17T05:45:43+08:00

3

如果您有 ssh 访问权限，您可能只想尝试 du -hc /var/lib/mysql （或 my.cnf 中设置的不同 datadir ） .

回复于 2024-04-17T05:45:43+08:00

1551

SELECT 
    table_name AS "Table",  
    round(((data_length + index_length) / 1024 / 1024), 2) as size   
FROM information_schema.TABLES  
WHERE table_schema = "YOUR_DATABASE_NAME"  
ORDER BY size DESC;

这会对大小进行排序（DB大小，以MB为单位） .

回复于 2024-04-17T05:45:43+08:00

18

以下是使用bash命令行解决此问题的另一种方法 .

for i in mysql -NB -e 'show databases'; do echo $i; mysql -e "SELECT table_name AS 'Tables', round(((data_length+index_length)/1024/1024),2) 'Size in MB' FROM information_schema.TABLES WHERE table_schema =\"$i\" ORDER BY (data_length + index_length) DESC" ; done

回复于 2024-04-17T05:45:43+08:00
1
使用Workbench可以轻松获取许多信息：
- 右键单击模式名称，然后单击“模式检查器” .
- 在结果窗口中，您有许多选项卡 . 第一个“信息”选项卡显示了以MB为单位的数据库大小的粗略估计 .
- 第二个选项卡“Tables”显示每个表的数据长度和其他详细信息 .
回复于 2024-04-17T05:45:43+08:00
6
如果您使用的是phpmyadmin，那么只需转到表结构即可

例如
```
Space usage
Data    1.5 MiB
Index   0   B
Total   1.5 Mi
```
回复于 2024-04-17T05:45:43+08:00
6
尝试以下shell命令（将 DB_NAME 替换为您的数据库名称）：

mysql -uroot <<<“SELECT table_name AS'Table'，round（（（data_length index_length）/ 1024/1024），2）'size in MB'FROM information_schema.TABLES WHERE table_schema = \”DB_NAME \“ORDER BY（ data_length index_length）DESC;“ |头

对于Drupal / drush解决方案，请检查以下示例脚本，该脚本将显示正在使用的最大表：
```
#!/bin/sh
DB_NAME=$(drush status --fields=db-name --field-labels=0 | tr -d '\r\n ')
drush sqlq "SELECT table_name AS 'Tables', round(((data_length + index_length) / 1024 / 1024), 2) 'Size in MB' FROM information_schema.TABLES WHERE table_schema = \"${DB_NAME}\" ORDER BY (data_length + index_length) DESC;" | head -n20
```
回复于 2024-04-17T05:45:43+08:00

SELECT TABLE_NAME AS table_name, 
table_rows AS QuantofRows, 
ROUND((data_length + index_length) /1024, 2 ) AS total_size_kb 
FROM information_schema.TABLES
WHERE information_schema.TABLES.table_schema = 'db'
ORDER BY (data_length + index_length) DESC;

以上所有2都是在mysql上测试的

回复于 2024-04-17T05:45:43+08:00

另一种显示行数和占用空间以及按顺序排序的方法 .

SELECT
     table_schema as `Database`,
     table_name AS `Table`,
     table_rows AS "Quant of Rows",
     round(((data_length + index_length) / 1024 / 1024/ 1024), 2) `Size in GB`
FROM information_schema.TABLES
WHERE table_schema = 'yourDatabaseName'
ORDER BY (data_length + index_length) DESC;

您必须在此查询中替换的唯一字符串是“yourDatabaseName” .

回复于 2024-04-17T05:45:43+08:00

76
改编自ChapMic的回答以满足我的特殊需求 .

仅指定数据库名称，然后按降序对所有表进行排序 - 从所选数据库中的LARGEST到SMALLEST表 . 只需要替换1个变量=您的数据库名称 .
```
SELECT 
table_name AS `Table`, 
round(((data_length + index_length) / 1024 / 1024), 2) AS `size`
FROM information_schema.TABLES 
WHERE table_schema = "YOUR_DATABASE_NAME_HERE"
ORDER BY size DESC;
```
回复于 2024-04-17T05:45:43+08:00

如何获取MySQL数据库表的大小？

15 回答

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