我有一个带有多个jar项目的父项目,我正在使用一个特定的子项目来组装所有jar和dependecies的zip包,实际上我添加了所有项目作为这个特定项目的dependecies . 有没有办法将jar和dependecies分成两个不同的拉链?
我能想到的最简单的方法是使用两个汇编描述符 .
pom.xml:
<build> <plugins> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-assembly-plugin</artifactId> <version>3.1.0</version> <executions> <execution> <phase>package</phase> <goals> <goal>single</goal> </goals> </execution> </executions> <configuration> <descriptors> <descriptor>src/assembly/assembly-myjars.xml</descriptor> <descriptor>src/assembly/assembly-dependencies.xml</descriptor> </descriptors> </configuration> </plugin> </plugins> </build>
assembly-myjars.xml:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0 http://maven.apache.org/xsd/assembly-2.0.0.xsd"> <id>myjars</id> <formats> <format>zip</format> </formats> <includeBaseDirectory>false</includeBaseDirectory> <dependencySets> <dependencySet> <includes> <include>your.groupId:*</include> </includes> </dependencySet> </dependencySets> </assembly>
assembly-dependencies.xml:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0 http://maven.apache.org/xsd/assembly-2.0.0.xsd"> <id>dependencies</id> <formats> <format>zip</format> </formats> <includeBaseDirectory>false</includeBaseDirectory> <dependencySets> <dependencySet> <excludes> <exclude>your.groupId:*</exclude> </excludes> </dependencySet> </dependencySets> </assembly>
1 回答
我能想到的最简单的方法是使用两个汇编描述符 .
pom.xml:
assembly-myjars.xml:
assembly-dependencies.xml: