使用vimeo apis时收到错误303无效签名

2 回答

• 0

  唐't know whether you'仍然有这个问题，但你可能会尝试使用scribe . 我've been developing an application for vimeo and relying heavily on Scribe to sign and send my requests. Here'是一个用于身份验证和签名以及发送请求的示例：

  private static OAuthService service;
    private static Token accessToken;
    private static String newline = System.getProperty("line.separator");
  
    public static void main(String[] args) throws Exception {
      // Replace these with your own api key and secret
  
      String apiKey = "YOUR_API_KEY"; //Give your own API Key
      String apiSecret = "YOUR_API_SECRET"; //Give your own API Secret
      String vimeoAPIURL = "http://vimeo.com/api/rest/v2";
      service = new ServiceBuilder().provider(VimeoApi.class).apiKey(apiKey).apiSecret(apiSecret).build();
  
      OAuthRequest request;
      Response response;
  
      accessToken = new Token("AN_INVALID_TOKEN_WILL", "REQUIRE_GETTING_A_NEW_ONE"); //Copy the new token you get here
  
      accessToken = checkToken(vimeoAPIURL, accessToken, service);
      if (accessToken == null) {
        return;
      }
   }
  
    /**
    * Checks the token to make sure it's still valid. If not, it pops up a dialog asking the user to
    * authenticate.
    */
    private static Token checkToken(String vimeoAPIURL, Token vimeoToken, OAuthService vimeoService) {
      if (vimeoToken == null) {
        vimeoToken = getNewToken(vimeoService);
      } else {
        OAuthRequest request = new OAuthRequest(Verb.GET, vimeoAPIURL);
        request.addQuerystringParameter("method", "vimeo.oauth.checkAccessToken");
        Response response = signAndSendToVimeo(request, "checkAccessToken", true);
        if (response.isSuccessful()
                && (response.getCode() != 200 || response.getBody().contains("<err code=\"302\"")
                || response.getBody().contains("<err code=\"401\""))) {
          vimeoToken = getNewToken(vimeoService);
        }
      }
      return vimeoToken;
    }
  
    /**
    * Gets authorization URL, pops up a dialog asking the user to authenticate with the url and the user
    * returns the authorization code
    *
    * @param service
    * @return
    */
    private static Token getNewToken(OAuthService service) {
      // Obtain the Authorization URL
      Token requestToken = service.getRequestToken();
      String authorizationUrl = service.getAuthorizationUrl(requestToken);
      do {
        String code = JOptionPane.showInputDialog("The token for the account (whatever)" + newline
                + "is either not set or is no longer valid." + newline
                + "Please go to the URL below and authorize this application." + newline
                + "Paste the code you're given on top of the URL here and click \'OK\'" + newline
                + "(click the 'x' or input the letter 'q' to cancel." + newline
                + "If you input an invalid code, I'll keep popping up).", authorizationUrl + "&permission=delete");
        if (code == null) {
          return null;
        }
        Verifier verifier = new Verifier(code);
        // Trade the Request Token and Verfier for the Access Token
        System.out.println("Trading the Request Token for an Access Token...");
        try {
          Token token = service.getAccessToken(requestToken, verifier);
          System.out.println(token); //Use this output to copy the token into your code so you don't have to do this over and over.
          return token;
        } catch (OAuthException ex) {
          int choice = JOptionPane.showConfirmDialog(null, "There was an OAuthException" + newline
                  + ex + newline
                  + "Would you like to try again?", "OAuthException", JOptionPane.YES_NO_OPTION);
          if (choice == JOptionPane.NO_OPTION) {
            break;
          }
        }
      } while (true);
      return null;
    }
  
    /**
    * Signs the request and sends it. Returns the response.
    *
    * @param request
    * @return response
    */
    public static Response signAndSendToVimeo(OAuthRequest request) throws org.scribe.exceptions.OAuthException {
      service.signRequest(accessToken, request);
      Response response = request.send();
      return response;
    }
  

  回复于 2024-05-08T12:33:08+08:00
• 0

  伙计我有几乎类似的问题 .

  我正在处理基本呼叫，一切正常 . 但我意识到基本只允许你查询60个视频 . 每页20个视频 . 下面是我尝试使用基本实现分页的链接，但代码仅适用于三个页面，即30个视频 .

  http://projects.tk-fn.com/controls/Vimeo/BKBVideoPage-Backup.html

  然后我尝试了高级api，允许每页50个和无限的视频 . 我能够完成所有OAuth实现，但现在的问题是，当我将它放在浏览器中时，url工作正常，但当我尝试进行JSONP ajax调用时，它不起作用 . :(

  http://projects.tk-fn.com/controls/Vimeo/OAuthSimple.html

  对于那些知道的人 . OAuth接受所有必需的参数，如Consumer_Key，Secret，NONE（随机字符串），timestamp，oauth_signature（使用整个url创建） .

  我找到了一个名为Simple OAuth的类并使用它 .

  REFRESH页面每次都能获得正确的URL . 网址不能多次使用 . Vimeo希望每个请求都有新网址 .

  回复于 2024-05-08T12:33:08+08:00