在Scala中将两个分隔符（和“”）拆分为[重复]

2 回答

• 0

  这可能对你有用 .

  def mySplit(str: String): List[String] = {
    var elems = List[String]()
  
    // break down by quotes first
    val quotes = str.split("\"")
    for(i <- 0 to quotes.length - 1) {
  
      if(i % 2 == 0) {
        // break down by commas second
        val subelems = quotes(i).split(",")
        for(j <- 0 to subelems.length - 1) {
          if(!subelems(j).isEmpty)
            elems = elems :+ subelems(j)
            // ignore empty elements
        }
  
      } else {
        // save "whole strings" and
        // don't break into commas
        elems = elems :+ quotes(i)
      }
    }
  
    return elems
  }
  

  像这样使用它：

  // quick test
  val str = "1,2018,Abc,2018-04-19,Abc,Abc,Abc,b,n,0,Abc,33,0,Abc,\"Sql, Xyz\",Abc,Abc"
  val list = mySplit(str)
  

  这是scalafiddle.io

  回复于 2024-04-23T22:21:33+08:00
• 1

  我已经完成了，使用下面的正则表达式

  val str= "1,2018,Abc,2018-04-19,Abc,Abc,Abc,b,n,0,Abc,33,0,Abc,\"Sql, Xyz\",Abc,Abc"
  val list=str.split(",(?=(?:[^\\\"]*\\\"[^\\\"]*\\\")*[^\\\"]*$)")
  
  list.foreach( x => println(x))
  

  回复于 2024-04-23T22:21:33+08:00