我的故事与一个有很多关系的章节有关，我有一个StoryChapter模型 .
我找到了所有故事的结果：
array(
(int) 0 => array(
'Story' => array(
'id' => '111',
'title' => 'First Story',
'question' => 'What do you want ?',
'description' => 'ezrsrfgq ergtqergq',
'date' => '2014-06-10',
'image' => '/uploads/stories/111.jpg',
'created' => '2014-06-10 07:51:35',
'modified' => '2014-06-13 12:45:43',
'created_by' => '1',
'original' => null,
'tags' => ''
),
'StoryChapter' => array(
(int) 0 => array(
'id' => '110',
'story_id' => '111',
'chapter_id' => '81',
'chapter_title' => 'Second Chapter',
'created' => '2014-06-11 00:00:00'
),
(int) 1 => array(
'id' => '109',
'story_id' => '111',
'chapter_id' => '80',
'chapter_title' => 'First Chapter',
'created' => '2014-06-13 00:00:00'
)
),
'StoryUser' => array(),
'StoryGroup' => array(),
'Favorite' => array(),
'Tag' => array()
),
(int) 1 => array(
'Story' => array(
'id' => '112',
'title' => 'Second Story',
'question' => 'What do you want ?',
'description' => 'edghs rthsghsx ghs rhsgrhsrtgh',
'date' => '2014-06-13',
'image' => '/uploads/stories/112.jpg',
'created' => '2014-06-13 07:43:18',
'modified' => '2014-06-13 07:43:18',
'created_by' => '1',
'original' => null,
'tags' => ''
),
'StoryChapter' => array(),
'StoryUser' => array(),
'StoryGroup' => array(),
'Favorite' => array(),
'Tag' => array()
)
）
我希望find函数只通过创建desc来命令StoryChapter而不影响找到的故事的顺序 .
我希望你明白我的意思 .
谢谢
1 回答
我通过在Story模型中的hasMany数组中添加顺序来解决问题