Cakephp中对关联表的多个引用-Java 学习之路

在将两个表（许多天气雷达帧属于气象雷达站点）与belongsTo和hasMany相关联之后，我希望在同一个表（和不同的条件）上生成两个“包含”的JSON，这样我只能列出有具体情况 . 我现在拥有的东西不起作用;它只将第二个包含写入JSON .

雷达站点表：

...
public function initialize(array $config)
{
    parent::initialize($config);

    $this->setTable('radar_site');

    $this->setDisplayField('radar_id');
    $this->setPrimaryKey('radar_id');

    $this->hasMany('FutureFrame', [
        'foreignKey' => 'radar_id'
    ]);

    $this->hasMany('RadarFrame', [
        'foreignKey' => 'radar_id'
    ]);
}
...

雷达框架表：

public function initialize(array $config)
{
    parent::initialize($config);

    $this->setTable('radar_frame');

    $this->setDisplayField('radar_id');
    $this->setPrimaryKey('radar_id');

    $this->belongsTo('RadarSite', [
        'foreignKey' => 'radar_id'
    ]);
}

控制器：

public function getRadarData()
{
    $radarInfo = 
    $this->RadarSite->find(
        'all',
        [
            'contain' => [
                'RadarFrame' =>[
                    'sort' => ['RadarFrame.frame_time' => 'DESC'],
                    'conditions' => [
                        'RadarFrame.frame_time >' => time() - 60*60,
                        'RadarFrame.file_on_server =' => 1,
                        'RadarFrame.radar_type =' => 'velocity'
                    ]
                ],
                'RadarFrame' =>[
                    'sort' => ['RadarFrame.frame_time' => 'DESC'],
                    'conditions' => [
                        'RadarFrame.frame_time >' => time() - 60*60,
                        'RadarFrame.file_on_server =' => 1,
                        'RadarFrame.radar_type =' => 'reflectivity'
                    ]
                ]                   
            ]
        ]

    );    
    $this->set('radarInfo', $radarInfo);
}

JSON输出：

...,{
        "radar_id": "KHGX",
        "radar_name": "Houston\/Galveston, TX",
        "elevation": 18,
        "tower_height": 20,
        "max_latitude": 31.6485,
        "min_latitude": 27.2476,
        "max_longitude": -92.4946,
        "min_longitude": -97.6634,
        "latitude": 29.4719,
        "longitude": -95.0792,
        "radar_frame": [
            {
                "radar_id": "KHGX",
                "radar_type": "reflectivity",
                "frame_time": 1495473662,
                "is_analyzed": 1,
                "average_speed": null,
                "average_direction": null,
                "file_on_server": 1
            },
            {
                "radar_id": "KHGX",
                "radar_type": "reflectivity",
                "frame_time": 1495473305,
                "is_analyzed": 1,
                "average_speed": null,
                "average_direction": null,
                "file_on_server": 1
            },
            {
                "radar_id": "KHGX",
                "radar_type": "reflectivity",
                "frame_time": 1495473002,
                "is_analyzed": 1,
                "average_speed": null,
                "average_direction": null,
                "file_on_server": 1
            }
        ]
    },...

这样做的正确方法是什么？有没有一种简单的方法可以为控制器添加别名，以区分两个包含查询？我正在使用CakePHP 3.0 .

谢谢！！

1 回答

由于您的条件是静态的，您可以将它们放入关系中：

雷达站点表：

public function initialize(array $config)
{
    parent::initialize($config);

    $this->setTable('radar_site');

    $this->setDisplayField('radar_id');
    $this->setPrimaryKey('radar_id');

    $this->hasMany('FutureFrame', [
        'foreignKey' => 'radar_id'
    ]);

    $this->hasMany('RadarFrameVelocity', [
       'className' => 'RadarFrame',
       'foreignKey' => 'radar_id',
       'conditions' => [
            'RadarFrame.frame_time >' => time() - 60*60,
            'RadarFrame.file_on_server =' => 1,
            'RadarFrame.radar_type =' => 'velocity'
        ]
    ]);

    $this->hasMany('RadarFrameReflectivity', [
        'className' => 'RadarFrame',
        'foreignKey' => 'radar_id',
        'conditions' => [
            'RadarFrame.frame_time >' => time() - 60*60,
            'RadarFrame.file_on_server =' => 1,
            'RadarFrame.radar_type =' => 'reflectivity'
        ]
    ]);
}

控制器：

public function getRadarData()
{
    $radarInfo = 
    $this->RadarSite->find(
        'all',
        [
            'contain' => [
                'RadarFrameVelocity' =>[
                    'sort' => ['RadarFrameVelocity.frame_time' => 'DESC']
                ],
                'RadarFrameReflectivity' => [
                    'sort' => ['RadarFrameReflectivity.frame_time' => 'DESC']
                ]                   
            ]
        ]

    );    
    $this->set('radarInfo', $radarInfo);
}

另见Associations - Linking Tables Together

回复于 2024-04-29T06:31:46+08:00

Cakephp中对关联表的多个引用

1 回答

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