好 . 让我们更清楚一点 .
我想要做的是以下内容:
我有一张像这样的 table ......
+---------+--------------------+--------------------------+
| id | name | email |
+---------+--------------------+--------------------------+
| 1 | karl | karl@email.com |
+---------+--------------------+--------------------------+
| 2 | fred | fred@email.com |
+---------+--------------------+--------------------------+
| 3 | christopher | chris@email.com |
+---------+--------------------+--------------------------+
我想要最终得到的是一个如下的新表:
+-----+---------------+---------------------+--------------+--------------------+
| id | name1 | email1 | name2 | email2 |
+-----+---------------+---------------------+--------------+--------------------+
| 1 | fred | fred@email.com | christopher | chris@email.com |
+-----+---------------+---------------------+--------------+--------------------+
| 2 | christopher | chris@email.com | karl | karl@email.com |
+-----+---------------+---------------------+--------------+--------------------+
| 3 | karl | karl@email.com | fred | fred@email.com |
+-----+---------------+---------------------+--------------+--------------------+
值是水平唯一的(id [1] .name1!= id [1] .name2)和vertical(id [1] .name1!= id [2] .name1) .
因此,此输出不可能:
+-----+---------------+---------------------+--------------+--------------------+
| id | name1 | email1 | name2 | email2 |
+-----+---------------+---------------------+--------------+--------------------+
| 1 | fred | fred@email.com | christopher | chris@email.com |
+-----+---------------+---------------------+--------------+--------------------+
| 2 | fred | fred@email.com | karl | karl@email.com |
+-----+---------------+---------------------+--------------+--------------------+
| 3 | karl | karl@email.com | karl | karl@email.com |
+-----+---------------+---------------------+--------------+--------------------+
我怎样才能轻松实现这一目标?
1 回答
我认为这个查询应该做的工作:
其中table是表的名称 . 我希望它会有所帮助 .