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iOS Google登录错误

提问于
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我正在尝试实现谷歌登录按钮，当我将以下行添加到我的AppDelegate.swift文件时，我收到此错误：

无法使用索引类型为“String”的类型'[String：AnyObject]'下标值

任何想法这个代码有什么问题？顺便说一句，此代码只是从谷歌页面复制并粘贴：https://developers.google.com/identity/sign-in/ios/sign-in?configured&ver=swift

func application(application: UIApplication,
    openURL url: NSURL, options options: [String: AnyObject]) -> Bool {
        return GIDSignIn.sharedInstance().handleURL(url,
            sourceApplication: options[UIApplicationOpenURLOptionsSourceApplicationKey],
            annotation: options[UIApplicationOpenURLOptionsAnnotationKey])
}

iOS Google Sign In error

谢谢

ios google-signin

2 回答

  • 12

    handleURL正在为sourceApplication和annotation查找类型为“String”的参数，但options提供了“AnyObject” . 将这些字典值转换为“String”应该这样做 .

    试试这个：

    Update: Swift 3

    func application(_ application: UIApplication,
                 open url: URL, options: [UIApplicationOpenURLOptionsKey: Any]) -> Bool
   return GIDSignIn.sharedInstance().handle(url,
       sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as? String,
       annotation: options[UIApplicationOpenURLOptionsKey.annotation] as? String)
}

    Swift 2

    func application(application: UIApplication,
    openURL url: NSURL, options: [String: AnyObject]) -> Bool {
        return GIDSignIn.sharedInstance().handleURL(url,
            sourceApplication: options[UIApplicationOpenURLOptionsSourceApplicationKey] as? String,
            annotation: options[UIApplicationOpenURLOptionsAnnotationKey] as? String)
}

    这也让我永远 . 希望有所帮助！

    回复于
  • 8

    Xcode 8 Swift 3

    func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
  return GIDSignIn.sharedInstance().handle(
  url,
  sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String,
  annotation: options[UIApplicationOpenURLOptionsKey.annotation])
}
    回复于

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