在下面发布了我的代码的seg fault erros . 我是C的新手,并且遇到了一些麻烦 . 基本上在我的主要部分我创建了一个struct node * head(指向struct节点的指针)并将其赋值为NULL . 然后我将struct node * head发送到push函数,该函数应该将用户定义的整数插入到列表的前面 . 我相信我在推送功能中遇到问题,任何帮助都会非常苛刻 .
〜谢谢
//node.h
struct node{
int val;
struct node* next;
};
int length(struct node *);
struct node* push(struct node *, int);
void print(struct node *, int);
//node.c
#include "./node.h"
#include<stdlib.h>
#include<stdio.h>
int length(struct node *current){
if(current->next != NULL)
return 1 + length(current->next);
else
return 1;
}
struct node* push(struct node *head, int num){
struct node *temp = malloc(sizeof(struct node));
temp->val = num;
temp->next = head;
head = temp;
return head;
}
void print(struct node* head, int size){
printf("The list is %i", size);
printf(" long \n");
struct node* temp;
temp = head;
while(temp != NULL){
printf("%d", temp->val);
printf(" ");
temp = temp->next;
}
printf(" \n");
}
//main program
#include "./node.h"
#include<stdlib.h>
#include<stdio.h>
int main(){
char ans;
int num;
struct node* head = NULL;
do{
printf("Enter a integer for linked list: ");
scanf("%d", &num);
head = push(head, num);
printf("Add another integer to linked list? (y or n) ");
scanf("%1s", &ans);
}while(ans == 'y');
print(head, length(head));
return 0;
}
1 回答
scanf
将使用%ns
将n+1
字符读入提供的缓冲区,因为空终止符 .使用大小为2的缓冲区(
char ans[2];
)并检查第一个字符(ans[0] == 'y'
) . 调用scanf
时,您也不再需要获取ans
的地址 .