retrofit2 rxjava2处理全局网络异常和自动身份验证-Java 学习之路

我有下一个处理错误的代码 . 此代码非常适合处理错误，但我想处理“未授权”错误 .

public class RxErrorHandlingCallAdapterFactory extends CallAdapter.Factory {

    private RxJava2CallAdapterFactory rxJavaCallAdapterFactory;
    private Context context;
    private Gson gson;

    public RxErrorHandlingCallAdapterFactory(Context context, Gson gson) {
        this.context = context;
        this.gson = gson;
        rxJavaCallAdapterFactory = RxJava2CallAdapterFactory.create();
    }

    public static CallAdapter.Factory create(Context context, Gson gson) {
        return new RxErrorHandlingCallAdapterFactory(context, gson);
    }

    @Nullable
    @Override
    public CallAdapter<?, ?> get(Type returnType, Annotation[] annotations, Retrofit retrofit) {
        return new RxCallAdapterWrapper<>(retrofit, rxJavaCallAdapterFactory.get(returnType, annotations, retrofit));
    }

    private class RxCallAdapterWrapper<R> implements CallAdapter<R, Observable<R>> {

        private final Retrofit retrofit;
        private final CallAdapter<R, ?> wrappedCallAdapter;

        public RxCallAdapterWrapper(Retrofit mRetrofit, CallAdapter<R, ?> wrapped) {
            this.retrofit = mRetrofit;
            this.wrappedCallAdapter = wrapped;
        }

        @Override
        public Type responseType() {
            return wrappedCallAdapter.responseType();
        }

        @SuppressWarnings("unchecked")
        @Override
        public Observable<R> adapt(@NonNull Call<R> call) {
            return ((Observable<R>) wrappedCallAdapter.adapt(call))
                    .onErrorResumeNext(new Function<Throwable, ObservableSource<? extends R>>() {
                @Override
                public ObservableSource<? extends R> apply(Throwable throwable) throws Exception {
                    return Observable.error(convertError(throwable));
                }
            });
        }

        private ErrorThrowable convertError(final Throwable throwable) {
            Error error = new Error(Error.ErrorCodes.UNKNOWN_ERROR, context.getString(com.inscreen.R.string.unknown_error));

            if (throwable instanceof ConnectException) {
                error = new Error(Error.ErrorCodes.SOCKET_TIMEOUT_EXCEPTION,
                        context.getString(com.inscreen.R.string.error_connection));
                return new ErrorThrowable(throwable, error);
            }

            if (throwable instanceof SocketTimeoutException) {
                error = new Error(Error.ErrorCodes.SOCKET_TIMEOUT_EXCEPTION,
                        context.getString(com.inscreen.R.string.error_socket_timeout));
                return new ErrorThrowable(throwable, error);
            }
            if (throwable instanceof HttpException) {
                HttpException exception = (HttpException) throwable;
                Response response = exception.response();
                if (response != null && !response.isSuccessful()) {
                    ResponseBody errorBody = response.errorBody();
                    if (errorBody != null) {
                        try {
                            error = gson.fromJson(errorBody.string(), Error.class);
                        } catch (JsonSyntaxException | IOException exc) {
                            return new ErrorThrowable(throwable, error);
                        }
                    }
                }
            }

            return new ErrorThrowable(throwable, error);
        }
    }

}

当错误代码"not authorised"我想自动登录 . 像这样https://stackoverflow.com/a/26201962/6805851但我不知道该怎么做 .

@SuppressWarnings("unchecked")
        @Override
        public Observable<R> adapt(@NonNull Call<R> call) {
            return ((Observable<R>) wrappedCallAdapter.adapt(call))
                    .onErrorResumeNext(new Function<Throwable, ObservableSource<? extends R>>() {
                @Override
                public ObservableSource<? extends R> apply(Throwable throwable) throws Exception {
                    if (errorrCodeNotAuthorized) {
                        return "AutorizationObservable".flatMap(return "OLD REQUEST OBSERVABLE");
                    } else {
                        return Observable.error(convertError(throwable));
                    }
                }
            });
        }

我如何在flatMap中返回“OLD REQUEST OBSERVABLE”或如何在登录后启动旧请求？

1 回答

我找到了解决方案 .

if (error.isNotAuthorized()) {
                                        UserManager userManager = Application.getAppComponent().getUserManager();
                                        String email = userManager.getEmail();
                                        String password = userManager.getPassword();
                                        return userManager.getLoginObservable(email, password)
                                                .flatMap(new Function<User, ObservableSource<R>>() {
                                                    @Override
                                                    public ObservableSource<R> apply(User user) throws Exception {
                                                        return ((Observable<R>) wrappedCallAdapter.adapt(call));
                                                    }
                                                });

回复于 2024-04-19T11:08:07+08:00

retrofit2 rxjava2处理全局网络异常和自动身份验证

1 回答

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