我的系统是Ubuntu 15.04 64bit . 我的python版本:
**:~$ python
Python 2.7.11 |Anaconda custom (64-bit)| (default, Dec 6 2015, 18:08:32)
[GCC 4.4.7 20120313 (Red Hat 4.4.7-1)] on linux2
我的ipython版本:
**:~$ ipython
Python 2.7.11 |Anaconda custom (64-bit)| (default, Dec 6 2015, 18:08:32)
Type "copyright", "credits" or "license" for more information.
IPython 4.2.0 -- An enhanced Interactive Python.
我使用 conda install matplotlib
, conda install numpy
和 conda install scipy
. 版本和位置
# packages in environment at /home/hust/anaconda2:
numpy 1.10.4 py27_1
matplotlib 1.5.1 np110py27_0
scipy 0.17.0 np110py27_3
在ipython中,
In[1] %matplotlib
Using matplotlib backend: Qt4Agg
In[2] from pylab import*
没关系 .
为了在jupyter笔记本中新建 python2
,我使用Kernels for Python 2中的这些命令
conda create -n ipykernel_py2 python=2 ipykernel
source activate ipykernel_py2
python -m ipykernel install --user
现在通过在终端输入 jupyter notebook
,新建一个 python2
. 我尝试使用 %matplotlib
In[1]: %matplotlib
ImportError Traceback (most recent call last)
<ipython-input-2-f64cd8484500> in <module>()
----> 1 get_ipython().magic(u'matplotlib')
/home/hust/.local/lib/python2.7/site-packages/IPython /core/interactiveshell.pyc in magic(self, arg_s)
2161 magic_name, _, magic_arg_s = arg_s.partition(' ')
2162 magic_name = magic_name.lstrip(prefilter.ESC_MAGIC)
-> 2163 return self.run_line_magic(magic_name, magic_arg_s)
2164
2165 #-------------------------------------------------------------------------
/home/hust/.local/lib/python2.7/site-packages/IPython/core/interactiveshell.pyc in run_line_magic(self, magic_name, line)
2082 kwargs['local_ns'] = sys._getframe(stack_depth).f_locals
2083 with self.builtin_trap:
-> 2084 result = fn(*args,**kwargs)
2085 return result
2086
<decorator-gen-106> in matplotlib(self, line)
/home/hust/.local/lib/python2.7/site-packages/IPython/core/magic.pyc in <lambda>(f, *a, **k)
191 # but it's overkill for just that one bit of state.
192 def magic_deco(arg):
--> 193 call = lambda f, *a, **k: f(*a, **k)
194
195 if callable(arg):
/home/hust/.local/lib/python2.7/site-packages/IPython/core/magics/pylab.pyc in matplotlib(self, line)
98 print("Available matplotlib backends: %s" % backends_list)
99 else:
--> 100 gui, backend = self.shell.enable_matplotlib(args.gui)
101 self._show_matplotlib_backend(args.gui, backend)
102
/home/hust/.local/lib/python2.7/site-packages/IPython/core/interactiveshell.pyc in enable_matplotlib(self, gui)
2937 """
2938 from IPython.core import pylabtools as pt
-> 2939 gui, backend = pt.find_gui_and_backend(gui, self.pylab_gui_select)
2940
2941 if gui != 'inline':
/home/hust/.local/lib/python2.7/site-packages/IPython/core/pylabtools.pyc in find_gui_and_backend(gui, gui_select)
258 """
259
--> 260 import matplotlib
261
262 if gui and gui != 'auto':
ImportError: No module named matplotlib
结果证明是错误的 .
我在conda环境中安装了 matplotlib
, scipy
和 numpy
. 它似乎在ipython中运行良好,但在jupyter笔记本中却没有 . 是什么原因?如果你能帮助我,我将非常感激 .
1 回答
我发现了问题 .
在终端:
但是在jupyter笔记本中,sys.path是:
然后我记得我使用以下代码创建了一个python2内核 .
在website的描述中,如果你在Python 3上运行Jupyter,你可以像这样设置一个Python 2内核 . 但实际上我在Python 2上运行Jupyter,之所以我不能在jupyter笔记本中新建一个python2脚本应该是别的东西 .
最后,我意识到通过pyenv掌握所有蟒蛇的环境会更好 . 我应该首先安装pyenv然后我只需要使用这些命令,
pyenv install anaconda-2.4.0
,pyenv global anaconda-2.4.0
和jupyter notebook
.