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从Android应用程序打开Whatsapp联系人列表

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我是android新手,并尝试执行以下任务: - 我想打开Whatsapp联系人列表并获取选定的联系人数据 . 我能够完成一半的工作 . Whatsapp联系人列表打开,但一旦我按任何联系人我的应用程序崩溃 . 这是我的代码:

要打开Whatsapp联系人列表:

btnChoose.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent intent = new Intent(Intent.ACTION_PICK);
            intent.setPackage("com.whatsapp");
            try{
                Toast.makeText(AddScheduleActivity.this, "going out activity", Toast.LENGTH_SHORT).show();
                startActivityForResult(intent, 1);
                Toast.makeText(AddScheduleActivity.this, "getting In activity", Toast.LENGTH_SHORT).show();
            } catch (Exception e) {
                Toast.makeText(AddScheduleActivity.this, "Whatsapp not found", Toast.LENGTH_SHORT).show();  //no activity found to handle this intent means whatsapp is not installed
            }
        }
    });

要获得选择: -

@Override
public void onActivityResult(int requestCode, int resultCode, Intent intent) {
    super.onActivityResult(requestCode, resultCode, intent);
    Toast.makeText(AddScheduleActivity.this, "Ok In", Toast.LENGTH_SHORT).show();

    switch (requestCode) {
        case 1:
            if(resultCode == RESULT_OK){
                if(intent.hasExtra("contact")){

                    Toast.makeText(AddScheduleActivity.this, "Ok working", Toast.LENGTH_SHORT).show();
                    Uri uri = intent.getData();
                    //Query the content uri
                    Cursor cursor = getContentResolver().query(uri, null, null, null, null);
                    cursor.moveToFirst();
                    // column index of the phone number
                    int  phoneIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
                    // column index of the contact name
                    int  nameIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
                    contactNumber = cursor.getString(phoneIndex);
                    name = cursor.getString(nameIndex);

                }
            }
            break;

        default:
            break;
    }
}

如果我没有选择任何联系并按回,那么在这种情况下他们不会崩溃

提前致谢 .

2 回答

  • 1

    终于自己解决了这个问题 . 这是编辑的代码:

    @Override
    public void onActivityResult(int requestCode, int resultCode, Intent intent) {
        super.onActivityResult(requestCode, resultCode, intent);
    
        switch (requestCode) {
            case 1:
                if(resultCode == RESULT_OK){
    
                    if(intent.hasExtra("contact")){
                        String number = intent.getStringExtra("contact");
    
                        Toast.makeText(AddScheduleActivity.this, number, Toast.LENGTH_LONG).show();
    
                    }
                }
                break;
    
            default:
                break;
        }
    }
    
  • 0

    intent.getdata() 将始终返回null .

    使用 intent.getExtras().getString("contact"); 获取联系号码 .

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