首页 文章

OleDB INSERT命令错误

提问于
浏览
8

我有一个数据库(我使用MS ACCESS)我有这个插入代码,我可以读取数据但写入时出错,我按照说明但它不起作用这里是我的代码

OleDbConnection con = new OleDbConnection(@" provider=Microsoft.ace.Oledb.12.0; data source=\\sisc-erelim\4_Printing\VTDB\DB\VirginiTEADB2.accdb; Persist Security Info=False");

private void button1_Click(object sender, EventArgs e)
        {
            try
            {
                OleDbCommand cmd = new OleDbCommand();
                cmd.CommandType = CommandType.Text;
                cmd.CommandText = "INSERT INTO Accountstbl (Username, Password)" + "VALUES ('" + textBox1.Text + "','" + textBox2.Text + "')";
                cmd.Parameters.AddWithValue("@Username", textBox1.Text);
                cmd.Parameters.AddWithValue("@Password", textBox2.Text);
                cmd.Connection = con;
                con.Open();
                cmd.ExecuteNonQuery();
            }
            catch (Exception ex)
            {
                textBox1.Text = ex.ToString();
            }

我总是遇到这个错误,

System.Data.OleDb.OleDbException: Syntax error in INSERT INTO statement.
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult)
   at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method)
   at System.Data.OleDb.OleDbCommand.ExecuteNonQuery()
   at VirginiTEAcorp.Form3.button1_Click(Object sender, EventArgs e) in C:\Documents and Settings\12-014s\My Documents\applications\Database\WindowsFormsApplication1\Form3.cs:line 34

4 回答

  • 9

    insert语句中需要一个空格:

    ssword)" + "VALUES ('"
    

    例如,在您的语句中,您已连接而不允许空格 .

    应该:

    ssword)" + " VALUES ('"
    

    例如 .

  • 0

    你可以这样:

    cmd.CommandText = "INSERT INTO Accountstbl (Username, [Password]) VALUES (@Username,@Password)";
                cmd.Parameters.AddWithValue("@Username", textBox1.Text);
                cmd.Parameters.AddWithValue("@Password", textBox2.Text);
    

    我希望这会奏效 .

    开心点 .

  • 1

    您定义了 @Username@Password 参数,但您从未在sql命令中使用过 .

    怎么样?

    cmd.CommandText = "INSERT INTO Accountstbl (Username, [Password]) VALUES (@Username, @Password)";
    cmd.Parameters.AddWithValue("@Username", textBox1.Text);
    cmd.Parameters.AddWithValue("@Password", textBox2.Text);
    cmd.Connection = con;
    con.Open();
    cmd.ExecuteNonQuery();
    

    你也应该在sql命令的方括号中使用 Password ,如 [Password] ,因为它在MS Access中是reserved keyword .

    如果你不这样做可能会导致错误;

    关键字“密码”附近的语法不正确

  • 0

    尝试改变这种方式

    cmd.CommandText = "INSERT INTO Accountstbl (Username, Password) VALUES (@Username,@Password)";
    

相关问题