程序只是读取表单并停止 .
//...
Socket client = server.accept();
BufferedReader in = new BufferedReader(new InputStreamReader(client.getInputStream()));
System.out.println("Request:");
while ((line = in.readLine()) != null)
if (line.length() > 0)
System.out.println("\t" + line);
else break;
in.close();
client.close();
当我尝试在浏览器上提交某个表单时：
Waiting for request...
Connection accepted.
Request:
POST /form.php HTTP/1.1
Host: x-x-x-x
Connection: keep-alive
Content-Length: 31
Cache-Control: max-age=0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Origin: http://neviat.us.to
User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36
Content-Type: application/x-www-form-urlencoded
Referer: http://x-x-x-x
Accept-Encoding: gzip,deflate,sdch
Accept-Language: pt-BR,pt;q=0.8,en-US;q=0.6,en;q=0.4
Connection closed.
我得到了 Content-Length ，但内容本身并没有 . ¬-我认为那可能是 else break; ，所以我把它取下来再试一次：
Waiting for request...
Connection accepted.
Request:
POST /buy.php HTTP/1.1
Host: x-x-x-x
Connection: keep-alive
Content-Length: 31
Cache-Control: max-age=0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Origin: http://neviat.us.to
User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36
Content-Type: application/x-www-form-urlencoded
Referer: http://x-x-x-x
Accept-Encoding: gzip,deflate,sdch
Accept-Language: pt-BR,pt;q=0.8,en-US;q=0.6,en;q=0.4
// stop here, waiting for stream...
但内容也不存在 .
我怎么才能得到它？
1 回答
更改：
至
0长度的行是完全有效的