这个问题在这里已有答案:
我正在尝试学习关于Protege的SPARQL查询,我已经添加了一些个人来查询电影本体,发现于:Movie Ontology
我有以下简单的sparql查询:
Query 1: Get all movies and actors having rating more than 7.0
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
PREFIX xsd: <http://www.w3.org/2001/XMLSchema#>
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX mov: <http://www.movieontology.org/2009/10/01/movieontology.owl#>
SELECT ?subject ?actors ?rating
WHERE {
?subject a mov:Movie;
mov:hasActor ?actors;
mov:imdbrating ?rating.
Filter(?rating > "7.0"^^xsd:double)
}
我得到了预期的结果:
问题是我在评级栏中不需要^^ xsd:double uri !!如何摆脱uri“^^ http://www.w3.org/2001/XMLSchema#double” . 提前致谢 !
1 回答
使用
str
获取词汇部分SELECT ?subject ?actors (str(?rating) AS ?r)