我有一个中间件,如果路由不允许他限制访问路由 . 我添加了: kernel.php
protected $middleware = [ \App\Http\Middleware\MyMiddlware::class,]
public function handle($request, Closure $next)
{
$response = $next($request);
$currentRoute = $request->route()->getName();
$accessibleMenu = $this->menu->where('route_name', $currentRoute)->first();
dd('middleware');
if ($this->auth->check() && !is_null($accessibleMenu)) {
$userRole = $request->user()->role()->first()->id;
if (!is_null($userRole ) && $userRole ==1) {
return $response;
}
}
return Response::make(view('noPermission'), 404);
}
路线:
Route::get('menu/list','MenuController@index')->name('menu-list');
控制器功能::
public function index($parent_id = null)
{
dd('executed');
$menus = $this->menu->orderBy('id', 'DESC')->paginate(5000);
return view('menu.index', compact('menus'));
}
现在为real:如果role id为2,则中间件应返回404视图而不执行路由 . 但它在屏幕上打印执行的字符串!
1.如果我删除或评论:
$response = $next($request);
它返回
Call to a member function getName() on null
- 如果我将路线注册移至
'web'=> [\ App \ Http \ Middleware \ EncryptCookies :: class,\ Illuminate \ Cookie \ Middleware \ AddQueuedCookiesToResponse :: class,\ Illuminate \ Session \ Middleware \ StartSession :: class,// \ Illuminate \ Session \ Middleware \ AuthenticateSession :: class,\ Illuminate \ View \ Middleware \ ShareErrorsFromSession :: class,\ App \ Http \ Middleware \ VerifyCsrfToken :: class,\ Illuminate \ Routing \ Middleware \ SubstituteBindings :: class,\ App \ Http \ Middleware \ Activity :: class,\ App \ Http \ Middleware \ MyMiddlware :: class,],
和评论:
$response = $next($request);
然后屏幕打印“中间件”和中间件工作
我的问题是为什么middlware允许函数执行,如果我使用它
$response = $next($request);
在第一个句柄功能?如果在 protected $middleware = []
数组中使用,为什么middlware不起作用并为 getName()
返回null?
laravel在kernel.php中说 - protected $ middleware = []:*这些中间件在每次请求应用程序时运行 .
为什么即使我限制访问后这也允许?
1 回答
通过这个阅读我有困难,但我认为你想改变2行:
删除
$response = $next($request);
改
return $response;
改为return $next($request);