我试图用jquery和php发送自己的电子邮件消息我希望消息的内容由jquery决定这是我的发送代码
$.ajax({
url: 'http://mywebpage.com/email.php',
type: 'POST',
contentType: 'application/json; charset=utf-8',
data:'test',
dataType: "text",
success: function(data){
console.log(data);
console.log("IT WORKED");
},
failure: function(result){
console.log("FAILED");
console.log(result);
}
});
这是我的PHP脚本
<?php
header('Access-Control-Allow-Origin: *');
header('Access-Control-Allow-Methods: POST, GET, OPTIONS');
header("Access-Control-Allow-Headers: Origin, X-Requested-With, Content-Type, Accept");
$to = "myemail@gmail.com";
$subject = "Test mail";
$message = $_POST["data"];
echo var_dump($_POST);
echo $message;
$from = "someonelse@example.com";
$headers = "From:" . $from;
mail($to,$subject,$message,$headers);
echo "Mail Sent.";
?>
电子邮件被发送,但$ _POST [“数据”]总是回来空了怎么办?
2 回答
data
应为以下格式或查询字符串 .您以错误的方式发送数据 . 请参阅下面的内容
然后你就可以使用$ _POST ['data']进行访问
谢谢