我试图在System Verilog中实例化一个模块 . 它在Modelsim中编译没有问题 . 当我试图模拟测试平台时,它说 .
# Loading work.testbench_serial_reader
# ** Error: (vsim-3033) C:/Modeltech_pe_edu_10.4a/examples/Serial_Read.sv(30): Instantiation of 'UARC' failed. The design unit was not found.
# Time: 0 ns Iteration: 0 Instance: /testbench_serial_reader File: C:/Modeltech_pe_edu_10.4a/examples/Serial_Read.sv
# Searched libraries:
# C:/Modeltech_pe_edu_10.4a/examples/work
# Error loading design
这是我的代码:
`default_nettype none
module testbench_serial_reader();
reg clk, serial_in;
reg [8:0] i;
wire [6:0] serial_out;
wire new_data;
reg data[22];
initial begin
clk <= 0;
serial_in <= 0;
data = {0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 1};
i = 0;
serial_in = data[i];
end
always #1 clk = ~clk;
always #16 i = i + 1;
always #16 serial_in = data[i];
UARC serial_reader( serial_in, clk, serial_out, new_data);
endmodule
module serial_reader
(
input wire serial_in_async
,input wire clk
,output reg [6:0] parallel_out
,output reg new_data
);
//reg [8:0] counter;
reg [7:0] state;
reg serial_in, serial_in_async2;
//reg [1:0] state;
reg [6:0] result;
//reg add;
initial
begin
state = 8'd0;
serial_in = 1'b1;
serial_in_async2 = 1'b1;
result = 7'd0;
new_data = 1'b0;
end
always @(posedge clk)
begin
serial_in = serial_in_async2;
serial_in_async2 = serial_in_async;
case (state)
8'd0: if(~serial_in) begin
state <= state + 1'd1;
end
8'd7: begin
if(~serial_in) begin
state <= state + 8'd1;
result <= 7'd0;
end else state <= 8'd0;
end
8'd23: begin
state <= state + 8'd1;
result <= result + serial_in;
end
8'd39: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b0000010;
end
end
9'd55: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b0000100;
end
end
9'd71: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b0001000;
end
end
9'd87: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b0010000;
end
end
9'd103: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b0100000;
end
end
9'd119: begin
state <= state + 8'd1;
if(serial_in) begin
result <= result + 7'b1000000;
end
new_data = 0;
end
9'd151: begin
if(serial_in) begin
state <= state + 1;
end else state <= 8'd136;
parallel_out = result;
new_data = 1;
end
9'd167: begin
if(serial_in) begin
state <= 0;
end else state <= 8'd152;
end
default: state <= state + 8'd1;
endcase
end
endmodule
知道问题可能是什么?当我编译和模拟verilog代码时,我没有得到实例化问题 . 只有系统Verilog . 我已经查看了许多代码示例,并且没有看到我如何进行实例化的问题 .
2 回答
应该
永远不要使用有序映射 . 这太容易出错了 . 使用命名映射:
问题就在于此
需要实例化的任何模块都必须遵循以下顺序:
因此,您应该将上面的行写为
尝试此更改,如果仍然出现问题,请回来 .