Update: 找到解决方案 . 你可以在帖子的最后看到它 .
我正在尝试使用 NSURLSession 对远程REST API执行POST请求 . 我们的想法是使用两个参数发出请求： deviceId 和 textContent .
问题是服务器无法识别这些参数 . 服务器部分正常工作，因为我使用POSTMAN为Google Chrome发送了一个POST，它运行得很好 .
这是我现在使用的代码：
NSString *deviceID = [[NSUserDefaults standardUserDefaults] objectForKey:@"deviceID"];
NSString *textContent = @"New note";
NSString *noteDataString = [NSString stringWithFormat:@"deviceId=%@&textContent=%@", deviceID, textContent];
NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration];
sessionConfiguration.HTTPAdditionalHeaders = @{
@"api-key" : @"API_KEY",
@"Content-Type" : @"application/json"
};
NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration];
NSURL *url = [NSURL URLWithString:@"http://url_to_manage_post_requests"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPBody = [noteDataString dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPMethod = @"POST";
NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// The server answers with an error because it doesn't receive the params
}];
[postDataTask resume];
我用 NSURLSessionUploadTask 尝试过相同的程序：
// ...
NSURL *url = [NSURL URLWithString:@"http://url_to_manage_post_requests"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPMethod = @"POST";
NSURLSessionUploadTask *uploadTask = [session uploadTaskWithRequest:request fromData:[noteDataString dataUsingEncoding:NSUTF8StringEncoding] completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// The server answers with an error because it doesn't receive the params
}];
[uploadTask resume];
有任何想法吗？
解决方案
我的方法的问题是我发送了不正确的 Content-Type 标头以及我的所有请求 . 因此，代码正常工作所需的唯一更改是删除 Content-Type = application/json HTTP标头 . 所以正确的代码是这样的：
NSString *deviceID = [[NSUserDefaults standardUserDefaults] objectForKey:@"deviceID"];
NSString *textContent = @"New note";
NSString *noteDataString = [NSString stringWithFormat:@"deviceId=%@&textContent=%@", deviceID, textContent];
NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration];
sessionConfiguration.HTTPAdditionalHeaders = @{
@"api-key" : @"API_KEY"
};
NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration];
NSURL *url = [NSURL URLWithString:@"http://url_to_manage_post_requests"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPBody = [noteDataString dataUsingEncoding:NSUTF8StringEncoding];
request.HTTPMethod = @"POST";
NSURLSessionDataTask *postDataTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// The server answers with an error because it doesn't receive the params
}];
[postDataTask resume];
与其他参数一起发送图像
如果你需要使用 NSURLSession 在这里发布图像和其他参数，你有一个例子：
NSString *deviceID = [[NSUserDefaults standardUserDefaults] objectForKey:@"deviceID"];
NSString *textContent = @"This is a new note";
// Build the request body
NSString *boundary = @"SportuondoFormBoundary";
NSMutableData *body = [NSMutableData data];
// Body part for "deviceId" parameter. This is a string.
[body appendData:[[NSString stringWithFormat:@"--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"%@\"\r\n\r\n", @"deviceId"] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithFormat:@"%@\r\n", deviceID] dataUsingEncoding:NSUTF8StringEncoding]];
// Body part for "textContent" parameter. This is a string.
[body appendData:[[NSString stringWithFormat:@"--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"%@\"\r\n\r\n", @"textContent"] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithFormat:@"%@\r\n", textContent] dataUsingEncoding:NSUTF8StringEncoding]];
// Body part for the attachament. This is an image.
NSData *imageData = UIImageJPEGRepresentation([UIImage imageNamed:@"ranking"], 0.6);
if (imageData) {
[body appendData:[[NSString stringWithFormat:@"--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"%@\"; filename=\"image.jpg\"\r\n", @"image"] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[@"Content-Type: image/jpeg\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:imageData];
[body appendData:[[NSString stringWithFormat:@"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
}
[body appendData:[[NSString stringWithFormat:@"--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]];
// Setup the session
NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration];
sessionConfiguration.HTTPAdditionalHeaders = @{
@"api-key" : @"55e76dc4bbae25b066cb",
@"Accept" : @"application/json",
@"Content-Type" : [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary]
};
// Create the session
// We can use the delegate to track upload progress
NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration delegate:self delegateQueue:nil];
// Data uploading task. We could use NSURLSessionUploadTask instead of NSURLSessionDataTask if we needed to support uploads in the background
NSURL *url = [NSURL URLWithString:@"URL_TO_UPLOAD_TO"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
request.HTTPMethod = @"POST";
request.HTTPBody = body;
NSURLSessionDataTask *uploadTask = [session dataTaskWithRequest:request completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
// Process the response
}];
[uploadTask resume];
7 回答
您可以尝试使用NSDictionary作为参数 . 以下内容将正确地将参数发送到JSON服务器 .
希望这会有所帮助（我试图用上面的方法对CSRF真实性问题进行排序 - 但它确实在NSDictionary中发送了参数） .
动机
有时我想从
Dictionary将 httpBody 序列化传递给Data时遇到一些错误，这在大多数情况下是由于错误的编码或由于Dictionary中的非符合对象而导致数据格式错误 .解决方案
根据您的要求，一个简单的解决方案是创建
String而不是Dictionary并将其转换为Data. 您有以下代码示例写在Objective-C和Swift 3.0上 .Objective-C
斯威夫特
你可以使用https://github.com/mxcl/OMGHTTPURLRQ
Swift 2.0 solution is here:
如果您使用的是Swift，Just库会为您执行此操作 . 它的自述文件示例：
Swaya 3改变了Teja Kumar Bethina的代码：