我使用以下代码打开 SFSafariViewController
的URL:
import UIKit
import SafariServices
class ViewController: UIViewController, UITextViewDelegate {
override func viewDidLoad() {
super.viewDidLoad()
openBrowser(url: "https://www.example.com")
}
fileprivate func openBrowser(url: String) {
let svc = SFSafariViewController(url: NSURL(string: url)! as URL, entersReaderIfAvailable: false)
svc.delegate = self
present(svc, animated: true, completion: nil)
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
}
}
extension ViewController: SFSafariViewControllerDelegate {
func safariViewController(_ controller: SFSafariViewController, didCompleteInitialLoad didLoadSuccessfully: Bool) {
}
func safariViewController(_ controller: SFSafariViewController, activityItemsFor URL: URL, title: String?) -> [UIActivity] {
return []
}
func safariViewControllerDidFinish(_ controller: SFSafariViewController) {
}
}
这非常有效 .
但如果该网站包含一个 target="_blank"
链接,我点击它没有任何反应 .
我知道 SFSafariViewController
不支持多个窗口或标签 .
但我认为应该有可能忽略 target="_blank"
并打开链接,就像没有 target="_blank"
一样 .
有没有办法达到这个目标?