PHP Graphql创建片段

我有这个问题 .

query{
    paintInputsUser{
        username,country, views, rol
    }
}

但我需要一种方法将这些值转换为一个独特的字段，在谷歌搜索我发现最好的方法是使用片段 . 我要这个：

query{
    ...paintInputsUser
}

但我找不到如何创建片段以及如何将其添加到架构中 .

这是我的paintInputsUser类型

<?php

namespace App\GraphQL\Type;
use App\GraphQL\Support\Type;
use GraphQL;
use DB;
use GraphQL\Type\Definition\ObjectType;
use App\Model\Win\Users;

class PaintInputUser extends ObjectType
{

    public function __construct(){
        $config = [
            'name' => 'PaintInputUser',
            'description' => 'Help to know which fields the creation and edition of user are available, and the respective data',
            'fields' => function() {
                return [
                    'username' => [
                        'type' => Type::nonNull(Type::string()),
                    ],
                    'country' => [
                        'type' => Type::listOf(Type::string()),
                        'resolve' => function($person) {
                            $countries = DB::select('select c.country from win_country c inner join win_user_country uc on uc.id_country = c.id_country inner join win_users u on u.id_user = uc.id_user where u.username = ?',[$person->username]);
                            $array = array();
                            foreach($countries as $country){
                                array_push($array,$country->country);
                            }
                            return $array;
                        }
                    ],
                    'cards' => [
                        'type' => Type::listOf(Type::string()),
                        'resolve' => function($person) {
                            $cards = DB::select('select c.card from win_cards c
                            inner join win_user_card_granted ucg on ucg.id_card = c.id_card
                            inner join win_users u on u.id_user = ucg.id_user
                            where u.username = ?',[$person->username]);

                            $array = array();
                            foreach($cards as $card){
                                array_push($array,$card->card);
                            }
                            return $array;

                        }
                    ],
                    'views' => [
                        'type' => Type::listOf(Type::string()),
                        'resolve' => function($person) {
                            $views = DB::select('select vp.view_name from win_views_principal vp
                            inner join win_user_view_granted uvg on uvg.id_view = vp.id_view_principal
                            inner join win_users u on u.id_user = uvg.id_user
                            where u.username = ?',[$person->username]);

                            $array = array();
                            foreach($views as $view){
                                array_push($array,$view->view_name);
                            }
                            return $array;
                        }
                    ],
                    'rol' => [
                        'type' => Type::listOf(Type::string()),
                        'resolve' => function($person) {
                            $roles = DB::select('select r.rolename from win_roles r
                            inner join win_user_role ur on ur.id_role = r.id_role
                            inner join win_users u on u.id_user = ur.id_user
                            where u.username = ?',[$person->username]);

                            $array = array();
                            foreach($roles as $rol){
                                array_push($array,$rol->rolename);
                            }
                            return $array;
                        }
                    ],
                ];
            }
        ];
        parent::__construct($config);
    }
}

请有人解释我如何实现包含paintInputsUser的片段 .