我需要能够准确地找到两个日期之间的月数，即使它们跨越不同年份 . 我有以下解决方案，我从这个StackOverflow thread得到，但它在日期跨越不同年份时失败 .
当它跨越一年时工作
from datetime import datetime
from dateutil.relativedelta import relativedelta
date1 = datetime.strptime('2010-01-01', '%Y-%m-%d')
date2 = datetime.strptime('2010-12-01', '%Y-%m-%d')
diff = relativedelta(date2, date1)
number_of_months = diff.months
print(number_of_months) # 11
当它跨越多年时失败
from datetime import datetime
from dateutil.relativedelta import relativedelta
date1 = datetime.strptime('2010-01-01', '%Y-%m-%d')
date2 = datetime.strptime('2012-02-01', '%Y-%m-%d')
diff = relativedelta(date2, date1)
number_of_months = diff.months
print(number_of_months) # 1
鉴于此，我考虑了以下解决方案：
from datetime import datetime
from dateutil.relativedelta import relativedelta
def month_diff(date1, date2):
if date1.year == date2.year:
diff = relativedelta(date2, date1)
number_of_months = diff.months
else:
num_of_days = (date2 - date1).days
number_of_months = num_of_days//30
print(number_of_months)
date1 = datetime.strptime('2010-01-01', '%Y-%m-%d')
date2 = datetime.strptime('2010-12-01', '%Y-%m-%d')
date3 = datetime.strptime('2010-01-01', '%Y-%m-%d')
date4 = datetime.strptime('2012-02-01', '%Y-%m-%d')
month_diff(date1, date2) # 11
month_diff(date3, date4) # 25
因此，我的问题是，是否有比我现有的更好的解决方案？
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