MongoDB Aggregation展开多个数组-Java 学习之路

这就是我的文档的样子

{
  code: "A2df",
  clicks: 7,
  countries: [{"country":"IN", clicks:5},{"country":"US", clicks:2}],
  domains: [{"domain":"a.com", clicks:4},{"country":"b.com", clicks:3}]
},
{
  code: "B3ws",
  clicks: 11,
  countries: [{"country":"IN", clicks:6},{"country":"ND", clicks:5}],
  domains: [{"domain":"a.com", clicks:7},{"country":"c.com", clicks:4}]
},
{
  code: "A2df",
  clicks: 5,
  countries: [{"country":"IN", clicks:2},{"country":"ND", clicks:3}],
  domains: [{"domain":"a.com", clicks:1},{"country":"c.com", clicks:4}]
}...

这就是我需要的：

{
  code: "A2df",
  clicks: 12,
  countries: [
    {
      "country": "IN",
      clicks: 7
    },
    {
      "country": "US",
      clicks: 2
    },
    {
      "country": "ND",
      clicks: 3
    }
  ],
  domains: [
    {
      "domain": "a.com",
      clicks: 5
    },
    {
      "country": "b.com",
      clicks: 3
    },
    {
      "country": "c.com",
      clicks: 4
    }
  ]
}

我知道如何在多个查询中执行此操作 . 我可以对点击进行组聚合和求和，展开数组然后对它们进行分组，然后对它们求和 . 但我想跳过向数据库发出三个请求然后合并三个结果的痛苦 .

在MongoDB中是否有一种方法可以在单个查询中完成所有这些操作 . 我无法改变文件的结构 . 任何帮助表示赞赏 . 即使这不能在单个查询中完成，也可以通过任何建议来减轻痛苦 . :)

这是我到目前为止尝试在单个查询中使用它：

[
  {
    $match: {
      date: {
        $gte: fromDate,
        $lt: toDate
      },
      brand_id: brandId,
      type: "item"
    }
  },
  {
    $unwind: "$countries"
  },
  {
    $group: {
      _id: {
        code: "$code",

      },
      clicks: {
        $sum: "$countries.clicks"
      },
      countries: {
        $push: "$countries"
      }
    }
  },
  {
    $unwind: "$domains"
  },
  {
    $group: {
      _id: {
        code: "$code",

      },
      clicks: {
        $sum: "$domains.clicks"
      },
      domains: {
        $push: "$domains"
      }
    }
  }
]

这将返回一个空数组，但如果我只是进行第一次展开和分组，它会为我提供所需的国家/地区输出 . 这就是我想要解决的问题，尝试在一个查询中获取所有内容 .

1 回答

db.test.aggregate([
  // Summarize clicks and collect countries and domains for each code
  {
    $group: {
      _id: "$code",
      clicks: { $sum: "$clicks" },
      countries: { $push: "$countries" },
      domains: { $push: "$domains" },
    }
  },
  // Unwind array of array of sub-countries
  {
    $unwind: "$countries"
  },
  // Unwind each array of sub-countries
  {
    $unwind: "$countries"
  },
  // Summarize clicks for each sub-country
  {
    $group: {
      _id: { code: "$_id", country: "$countries.country"},
      clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group 
      countryClick: { $sum: "$countries.clicks" },
      domains: { $first: "$domains" }, // Keep domains
    }
  },
  // Collect sub-countries into embedded document
  {
    $group: {
      _id: "$_id.code",
      clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group 
      countries: { $push: { country: "$_id.country", clicks: "$countryClick" } },
      domains: { $first: "$domains" }, // Keep sub-domains
    }
  },
  // Unwind array of array of sub-domains
  {
    $unwind: "$domains"
  },
  // Unwind each array of sub-domains
  {
    $unwind: "$domains"
  },
  // Summarize clicks for each sub-domain
  {
    $group: {
      _id: { code: "$_id", domain: "$domains.domain", country: "$domains.country" },
      clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group 
      domainClick: { $sum: "$domains.clicks" },
      countries: { $first: "$countries" }, // Keep sub-countries
    }
  },
  // Collect sub-domains into embedded document
  {
    $group: {
      _id: "$_id.code",
      clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group 
      domains: { $push: { domain: "$_id.domain", country: "$_id.country", clicks: "$domainClick" } },
      countries: { $first: "$countries" }, // Keep sub-countries
    }
  },
]).pretty()

回复于 2024-04-30T21:07:57+08:00

MongoDB Aggregation展开多个数组

1 回答

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