将JSON反序列化为C＃动态对象？-Java 学习之路

822

有没有办法将JSON内容反序列化为C＃4动态类型？为了使用DataContractJsonSerializer，跳过创建一堆类会很不错 .

24 回答

587

最简单的方法是

只是包括这个dll

使用这样的代码

dynamic json = new JDynamic("{a:'abc'}");
//json.a is a string "abc"

dynamic json = new JDynamic("{a:3.1416}");
//json.a is 3.1416m

dynamic json = new JDynamic("{a:1}");
//json.a is

dynamic json = new JDynamic("[1,2,3]");
/json.Length/json.Count is 3
//And you can use json[0]/ json[2] to get the elements

dynamic json = new JDynamic("{a:[1,2,3]}");
//json.a.Length /json.a.Count is 3.
//And you can use  json.a[0]/ json.a[2] to get the elements

dynamic json = new JDynamic("[{b:1},{c:1}]");
//json.Length/json.Count is 2.
//And you can use the  json[0].b/json[1].c to get the num.

回复于 2024-04-24T21:15:16+08:00

7
有一个名为SimpleJson的C＃轻量级json库，可以在http://simplejson.codeplex.com找到https://github.com/facebook-csharp-sdk/simple-json

它支持.net 3.5，silverlight和windows phone 7 .

支持.net 4.0的动态

也可以作为nuget包安装
```
Install-Package SimpleJson
```
回复于 2024-04-24T21:15:16+08:00

如果您乐意依赖 System.Web.Helpers 程序集，则可以使用Json类：

dynamic data = Json.Decode(json);

它作为.NET 4框架的additional download包含在MVC框架中 . 如果有帮助，一定要给Vlad一个upvote！但是，如果您不能假设客户端环境包含此DLL，请继续阅读 .

建议采用另一种反序列化方法here . 我稍微修改了代码以修复错误并适合我的编码风格 . 您只需要此代码以及项目中对 System.Web.Extensions 的引用：

using System;
using System.Collections;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Dynamic;
using System.Linq;
using System.Text;
using System.Web.Script.Serialization;

public sealed class DynamicJsonConverter : JavaScriptConverter
{
    public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
    {
        if (dictionary == null)
            throw new ArgumentNullException("dictionary");

        return type == typeof(object) ? new DynamicJsonObject(dictionary) : null;
    }

    public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
    {
        throw new NotImplementedException();
    }

    public override IEnumerable<Type> SupportedTypes
    {
        get { return new ReadOnlyCollection<Type>(new List<Type>(new[] { typeof(object) })); }
    }

    #region Nested type: DynamicJsonObject

    private sealed class DynamicJsonObject : DynamicObject
    {
        private readonly IDictionary<string, object> _dictionary;

        public DynamicJsonObject(IDictionary<string, object> dictionary)
        {
            if (dictionary == null)
                throw new ArgumentNullException("dictionary");
            _dictionary = dictionary;
        }

        public override string ToString()
        {
            var sb = new StringBuilder("{");
            ToString(sb);
            return sb.ToString();
        }

        private void ToString(StringBuilder sb)
        {
            var firstInDictionary = true;
            foreach (var pair in _dictionary)
            {
                if (!firstInDictionary)
                    sb.Append(",");
                firstInDictionary = false;
                var value = pair.Value;
                var name = pair.Key;
                if (value is string)
                {
                    sb.AppendFormat("{0}:\"{1}\"", name, value);
                }
                else if (value is IDictionary<string, object>)
                {
                    new DynamicJsonObject((IDictionary<string, object>)value).ToString(sb);
                }
                else if (value is ArrayList)
                {
                    sb.Append(name + ":[");
                    var firstInArray = true;
                    foreach (var arrayValue in (ArrayList)value)
                    {
                        if (!firstInArray)
                            sb.Append(",");
                        firstInArray = false;
                        if (arrayValue is IDictionary<string, object>)
                            new DynamicJsonObject((IDictionary<string, object>)arrayValue).ToString(sb);
                        else if (arrayValue is string)
                            sb.AppendFormat("\"{0}\"", arrayValue);
                        else
                            sb.AppendFormat("{0}", arrayValue);

                    }
                    sb.Append("]");
                }
                else
                {
                    sb.AppendFormat("{0}:{1}", name, value);
                }
            }
            sb.Append("}");
        }

        public override bool TryGetMember(GetMemberBinder binder, out object result)
        {
            if (!_dictionary.TryGetValue(binder.Name, out result))
            {
                // return null to avoid exception.  caller can check for null this way...
                result = null;
                return true;
            }

            result = WrapResultObject(result);
            return true;
        }

        public override bool TryGetIndex(GetIndexBinder binder, object[] indexes, out object result)
        {
            if (indexes.Length == 1 && indexes[0] != null)
            {
                if (!_dictionary.TryGetValue(indexes[0].ToString(), out result))
                {
                    // return null to avoid exception.  caller can check for null this way...
                    result = null;
                    return true;
                }

                result = WrapResultObject(result);
                return true;
            }

            return base.TryGetIndex(binder, indexes, out result);
        }

        private static object WrapResultObject(object result)
        {
            var dictionary = result as IDictionary<string, object>;
            if (dictionary != null)
                return new DynamicJsonObject(dictionary);

            var arrayList = result as ArrayList;
            if (arrayList != null && arrayList.Count > 0)
            {
                return arrayList[0] is IDictionary<string, object> 
                    ? new List<object>(arrayList.Cast<IDictionary<string, object>>().Select(x => new DynamicJsonObject(x))) 
                    : new List<object>(arrayList.Cast<object>());
            }

            return result;
        }
    }

    #endregion
}

你可以像这样使用它：

string json = ...;

var serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new[] { new DynamicJsonConverter() });

dynamic obj = serializer.Deserialize(json, typeof(object));

所以，给定一个JSON字符串：

{
  "Items":[
    { "Name":"Apple", "Price":12.3 },
    { "Name":"Grape", "Price":3.21 }
  ],
  "Date":"21/11/2010"
}

以下代码将在运行时运行：

dynamic data = serializer.Deserialize(json, typeof(object));

data.Date; // "21/11/2010"
data.Items.Count; // 2
data.Items[0].Name; // "Apple"
data.Items[0].Price; // 12.3 (as a decimal)
data.Items[1].Name; // "Grape"
data.Items[1].Price; // 3.21 (as a decimal)

回复于 2024-04-24T21:15:16+08:00

试试这个 -

var units = new { Name = "Phone", Color= "White" };
    var jsonResponse = JsonConvert.DeserializeAnonymousType(json, units );

回复于 2024-04-24T21:15:16+08:00

523

为此，我将使用JSON.NET对JSON流进行低级解析，然后从 ExpandoObject 类的实例中构建对象层次结构 .

回复于 2024-04-24T21:15:16+08:00

使用包含在该库中的 JObject 类可以动态地反序列化JSON.NET . 我的JSON字符串代表这些类：

public class Foo {
   public int Age {get;set;}
   public Bar Bar {get;set;}
}

public class Bar {
   public DateTime BDay {get;set;}
}

现在我们反序列化字符串而不引用上面的类：

var dyn = JsonConvert.DeserializeObject<JObject>(jsonAsFooString);

JProperty propAge = dyn.Properties().FirstOrDefault(i=>i.Name == "Age");
if(propAge != null) {
    int age = int.Parse(propAge.Value.ToString());
    Console.WriteLine("age=" + age);
}

//or as a one-liner:
int myage = int.Parse(dyn.Properties().First(i=>i.Name == "Age").Value.ToString());

或者如果你想更深入：

var propBar = dyn.Properties().FirstOrDefault(i=>i.Name == "Bar");
if(propBar != null) {
    JObject o = (JObject)propBar.First();
    var propBDay = o.Properties().FirstOrDefault (i => i.Name=="BDay");
    if(propBDay != null) {
        DateTime bday = DateTime.Parse(propBDay.Value.ToString());
        Console.WriteLine("birthday=" + bday.ToString("MM/dd/yyyy"));
    }
}

//or as a one-liner:
DateTime mybday = DateTime.Parse(((JObject)dyn.Properties().First(i=>i.Name == "Bar").First()).Properties().First(i=>i.Name == "BDay").Value.ToString());

有关完整示例，请参阅post .

回复于 2024-04-24T21:15:16+08:00

您可以扩展JavaScriptSerializer以递归方式将它创建的字典复制到expando对象，然后动态使用它们：

static class JavaScriptSerializerExtensions
{
    public static dynamic DeserializeDynamic(this JavaScriptSerializer serializer, string value)
    {
        var dictionary = serializer.Deserialize<IDictionary<string, object>>(value);
        return GetExpando(dictionary);
    }

    private static ExpandoObject GetExpando(IDictionary<string, object> dictionary)
    {
        var expando = (IDictionary<string, object>)new ExpandoObject();

        foreach (var item in dictionary)
        {
            var innerDictionary = item.Value as IDictionary<string, object>;
            if (innerDictionary != null)
            {
                expando.Add(item.Key, GetExpando(innerDictionary));
            }
            else
            {
                expando.Add(item.Key, item.Value);
            }
        }

        return (ExpandoObject)expando;
    }
}

然后你只需要为你定义扩展的命名空间使用using语句（考虑在System.Web.Script.Serialization中定义它们...另一个技巧是不使用命名空间，那么你不需要使用完全声明）你可以像这样消费它们：

var serializer = new JavaScriptSerializer();
var value = serializer.DeserializeDynamic("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

var name = (string)value.Name; // Jon Smith
var age = (int)value.Age;      // 42

var address = value.Address;
var city = (string)address.City;   // New York
var state = (string)address.State; // NY

回复于 2024-04-24T21:15:16+08:00

使用Json.NET非常简单：

dynamic stuff = JsonConvert.DeserializeObject("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

还 using Newtonsoft.Json.Linq ：

dynamic stuff = JObject.Parse("{ 'Name': 'Jon Smith', 'Address': { 'City': 'New York', 'State': 'NY' }, 'Age': 42 }");

string name = stuff.Name;
string address = stuff.Address.City;

文件： Querying JSON with dynamic

回复于 2024-04-24T21:15:16+08:00

72

看看我在CodeProject上写的文章，它正是回答了这个问题：

Dynamic types with JSON.NET

在这里重新发布所有内容的方式太多了，甚至更少，因为该文章附带了密钥/所需的源文件 .

回复于 2024-04-24T21:15:16+08:00

要获得ExpandoObject：

using Newtonsoft.Json;
using Newtonsoft.Json.Converters;

Container container = JsonConvert.Deserialize<Container>(jsonAsString, new ExpandoObjectConverter());

回复于 2024-04-24T21:15:16+08:00

如何使用动态和JavaScriptSerializer解析easy json

请添加 System.Web.Extensions 的引用，并在顶部添加此命名空间 using System.Web.Script.Serialization;

public static void EasyJson()
{
    var jsonText = @"{
        ""some_number"": 108.541, 
        ""date_time"": ""2011-04-13T15:34:09Z"", 
        ""serial_number"": ""SN1234""
    }";

    var jss = new JavaScriptSerializer();
    var dict = jss.Deserialize<dynamic>(jsonText);

    Console.WriteLine(dict["some_number"]); 
    Console.ReadLine();
}

如何使用动态＆JavaScriptSerializer解析嵌套和复杂的json

请添加 System.Web.Extensions 的引用，并在顶部添加此命名空间 using System.Web.Script.Serialization;

public static void ComplexJson()
{
    var jsonText = @"{
        ""some_number"": 108.541, 
        ""date_time"": ""2011-04-13T15:34:09Z"", 
        ""serial_number"": ""SN1234"",
        ""more_data"": {
            ""field1"": 1.0,
            ""field2"": ""hello""
        }
    }";

    var jss = new JavaScriptSerializer();
    var dict = jss.Deserialize<dynamic>(jsonText);

    Console.WriteLine(dict["some_number"]); 
    Console.WriteLine(dict["more_data"]["field2"]);
    Console.ReadLine();
}

回复于 2024-04-24T21:15:16+08:00

285

我创建了一个使用Expando Objects的DynamicJsonConverter的新版本 . 我使用了expando对象，因为我想使用Json.net将动态序列化为json .

using System;
using System.Collections;
using System.Collections.Generic;
using System.Collections.ObjectModel;
using System.Dynamic;
using System.Web.Script.Serialization;

public static class DynamicJson
{
    public static dynamic Parse(string json)
    {
        JavaScriptSerializer jss = new JavaScriptSerializer();
        jss.RegisterConverters(new JavaScriptConverter[] { new DynamicJsonConverter() });

        dynamic glossaryEntry = jss.Deserialize(json, typeof(object)) as dynamic;
        return glossaryEntry;
    }

    class DynamicJsonConverter : JavaScriptConverter
    {
        public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
        {
            if (dictionary == null)
                throw new ArgumentNullException("dictionary");

            var result = ToExpando(dictionary);

            return type == typeof(object) ? result : null;
        }

        private static ExpandoObject ToExpando(IDictionary<string, object> dictionary)
        {
            var result = new ExpandoObject();
            var dic = result as IDictionary<String, object>;

            foreach (var item in dictionary)
            {
                var valueAsDic = item.Value as IDictionary<string, object>;
                if (valueAsDic != null)
                {
                    dic.Add(item.Key, ToExpando(valueAsDic));
                    continue;
                }
                var arrayList = item.Value as ArrayList;
                if (arrayList != null && arrayList.Count > 0)
                {
                    dic.Add(item.Key, ToExpando(arrayList));
                    continue;
                }

                dic.Add(item.Key, item.Value);
            }
            return result;
        }

        private static ArrayList ToExpando(ArrayList obj)
        {
            ArrayList result = new ArrayList();

            foreach (var item in obj)
            {
                var valueAsDic = item as IDictionary<string, object>;
                if (valueAsDic != null)
                {
                    result.Add(ToExpando(valueAsDic));
                    continue;
                }

                var arrayList = item as ArrayList;
                if (arrayList != null && arrayList.Count > 0)
                {
                    result.Add(ToExpando(arrayList));
                    continue;
                }

                result.Add(item);
            }
            return result;
        }

        public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
        {
            throw new NotImplementedException();
        }

        public override IEnumerable<Type> SupportedTypes
        {
            get { return new ReadOnlyCollection<Type>(new List<Type>(new[] { typeof(object) })); }
        }
    }
}

回复于 2024-04-24T21:15:16+08:00

4
您可以使用System.Web.Helpers.Json执行此操作 - 它的Decode方法返回一个动态对象，您可以根据需要进行遍历 .

它包含在System.Web.Helpers程序集（.NET 4.0）中 .
```
var dynamicObject = Json.Decode(jsonString);
```
回复于 2024-04-24T21:15:16+08:00

.Net 4.0有一个内置库来执行此操作：

using System.Web.Script.Serialization;
JavaScriptSerializer jss = new JavaScriptSerializer();
var d=jss.Deserialize<dynamic>(str);

这是最简单的方法 .

回复于 2024-04-24T21:15:16+08:00

5

它可能有点晚了，但是您想要的对象DynamicJSONObject包含在ASP.NET Web Pages包中的System.Web.Helpers.dll中，该包是WebMatrix的一部分 .

回复于 2024-04-24T21:15:16+08:00

简单的“字符串json数据”到没有任何第三方dll的对象

WebClient client = new WebClient();
string getString = client.DownloadString("https://graph.facebook.com/zuck");


JavaScriptSerializer serializer = new JavaScriptSerializer(); 
dynamic item = serializer.Deserialize<object>(getString);
string name = item["name"];

//note: JavaScriptSerializer in this namespaces
//System.Web.Script.Serialization.JavaScriptSerializer

注意：您还可以使用自定义对象 .

Personel item = serializer.Deserialize<Personel>(getString);

回复于 2024-04-24T21:15:16+08:00

JsonFx可以将json反序列化为动态对象 .

https://github.com/jsonfx/jsonfx

序列化到/从动态类型（.NET 4.0的默认值）：

var reader = new JsonReader(); var writer = new JsonWriter();

string input = @"{ ""foo"": true, ""array"": [ 42, false, ""Hello!"", null ] }";
dynamic output = reader.Read(input);
Console.WriteLine(output.array[0]); // 42
string json = writer.Write(output);
Console.WriteLine(json); // {"foo":true,"array":[42,false,"Hello!",null]}

回复于 2024-04-24T21:15:16+08:00

使用Newtonsoft.Json的另一种方法：

dynamic stuff = Newtonsoft.Json.JsonConvert.DeserializeObject("{ color: 'red', value: 5 }");
string color = stuff.color;
int value = stuff.value;

回复于 2024-04-24T21:15:16+08:00

使用DataSet（C＃）使用javascript简单函数创建json流，使用DataSet输入创建json（多表数据集）[[{a：1，b：2，c：3}，{a：3，b：5，c ：6}]，[{A：23，b：45，C：35}，{一个：58，b：59，C：45}]]

只是客户端使用eval例如

var d = eval（'[[{a：1，b：2，c：3}，{a：3，b：5，c：6}]，[{a：23，b：45，c：35 }，{一个：58，b：59，C：45}]]'）

然后用

d [0] [0] .a //从表0第0行输出1

d [1] [1] .b //从表1第1行中取出59

//create by Behnam Mohammadi And Saeed Ahmadian
public string jsonMini(DataSet ds)
{
    int t=0, r=0, c=0;
    string stream = "[";

    for (t = 0; t < ds.Tables.Count; t++)
    {
        stream += "[";
        for (r = 0; r < ds.Tables[t].Rows.Count; r++)
        {
            stream += "{";
            for (c = 0; c < ds.Tables[t].Columns.Count; c++)
            {
                stream += ds.Tables[t].Columns[c].ToString() + ":'" + ds.Tables[t].Rows[r][c].ToString() + "',";
            }
            if(c>0)
                stream = stream.Substring(0, stream.Length - 1);
            stream += "},";
        }
        if(r>0)
            stream = stream.Substring(0, stream.Length - 1);
        stream += "],";
    }
    if(t>0)
        stream = stream.Substring(0, stream.Length - 1);
    stream += "];";
    return stream;
}

回复于 2024-04-24T21:15:16+08:00

4
你可以用 using Newtonsoft.Json
```
var jRoot = 
 JsonConvert.DeserializeObject<dynamic>(Encoding.UTF8.GetString(resolvedEvent.Event.Data));
```
resolvedEvent.Event.Data 是我从调用核心事件得到的回应 .
回复于 2024-04-24T21:15:16+08:00

使用Cinchoo ETL - 一个可用于将json解析为动态对象的开源库

string json = @"{
    ""key1"": [
        {
            ""action"": ""open"",
            ""timestamp"": ""2018-09-05 20:46:00"",
            ""url"": null,
            ""ip"": ""66.102.6.98""
        }
    ]
}";
using (var p = ChoJSONReader.LoadText(json)
    .WithJSONPath("$.*")
    )
{
    foreach (var rec in p)
    {
        Console.WriteLine("action: " + rec.action);
        Console.WriteLine("timestamp: " + rec.timestamp);
        Console.WriteLine("url: " + rec.url);
        Console.WriteLine("ip: " + rec.ip);
    }
}

Output:

action: open
timestamp: 2018-09-05 20:46:00
url: http://www.google.com
ip: 66.102.6.98

免责声明：我是这个图书馆的作者 .

回复于 2024-04-24T21:15:16+08:00

我在我的代码中使用这样的，它工作正常

using System.Web.Script.Serialization;
JavaScriptSerializer oJS = new JavaScriptSerializer();
RootObject oRootObject = new RootObject();
oRootObject = oJS.Deserialize<RootObject>(Your JSon String);

回复于 2024-04-24T21:15:16+08:00

6
另一种选择是“将JSON粘贴为类”，以便可以快速轻松地反序列化 .
- 只需复制整个JSON即可
- 在VS中：单击编辑>选择性粘贴>将JSON粘贴为类
这是一个更好的解释n piccas ... https://blogs.msdn.microsoft.com/webdev/2012/12/18/paste-json-as-classes-in-asp-net-and-web-tools-2012-2-rc/
回复于 2024-04-24T21:15:16+08:00

我使用：http://json2csharp.com/来获取表示Json对象的A类 .

输入：

{
   "name":"John",
   "age":31,
   "city":"New York",
   "Childs":[
      {
         "name":"Jim",
         "age":11
      },
      {
         "name":"Tim",
         "age":9
      }
   ]
}

输出：

public class Child
{
    public string name { get; set; }
    public int age { get; set; }
}

public class Person
{
    public string name { get; set; }
    public int age { get; set; }
    public string city { get; set; }
    public List<Child> Childs { get; set; }
}

之后我使用Newtonsoft.Json来填充类：

using Newtonsoft.Json;

namespace GitRepositoryCreator.Common
{
    class JObjects
    {
        public static string Get(object p_object)
        {
            return JsonConvert.SerializeObject(p_object);
        }
        internal static T Get<T>(string p_object)
        {
            return JsonConvert.DeserializeObject<T>(p_object);
        }
    }
}

你可以这样称呼它：

Person jsonClass = JObjects.Get<Person>(stringJson);

string stringJson = JObjects.Get(jsonClass);

PS:

如果您的json变量名称不是有效的C＃名称（名称以 $ 开头），您可以像这样修复：

public class Exception
{
   [JsonProperty(PropertyName = "$id")]
   public string id { get; set; }
   public object innerException { get; set; }
   public string message { get; set; }
   public string typeName { get; set; }
   public string typeKey { get; set; }
   public int errorCode { get; set; }
   public int eventId { get; set; }
}

回复于 2024-04-24T21:15:16+08:00

将JSON反序列化为C＃动态对象？

24 回答

如何使用动态和JavaScriptSerializer解析easy json

如何使用动态＆JavaScriptSerializer解析嵌套和复杂的json

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