搜索特定值的所有表中的所有字段（Oracle）-Java 学习之路

是否有可能在每个表的每个字段中搜索Oracle中的特定值？

在一些表中有数百个表有数千行，所以我知道这可能需要很长时间才能查询 . 但我唯一知道的是，我想要查询的字段的值是 1/22/2008P09RR8 . <

我已经尝试使用下面的这个语句根据我认为应该命名的内容找到一个合适的列，但它没有返回任何结果 .

SELECT * from dba_objects 
WHERE object_name like '%DTN%'

这个数据库绝对没有文档，我不知道该字段的来源 .

有什么想法吗？

15 回答

我修改了Flood的脚本，为每个表执行一次，而不是为每个表的每一列执行，以便更快地执行 . 它需要Oracle 11g或更高版本 .

set serveroutput on size 100000

declare
    v_match_count integer;
    v_counter integer;

    -- The owner of the tables to search through (case-sensitive)
    v_owner varchar2(255) := 'OWNER_NAME';
    -- A string that is part of the data type(s) of the columns to search through (case-insensitive)
    v_data_type varchar2(255) := 'CHAR';
    -- The string to be searched for (case-insensitive)
    v_search_string varchar2(4000) := 'FIND_ME';

    -- Store the SQL to execute for each table in a CLOB to get around the 32767 byte max size for a VARCHAR2 in PL/SQL
    v_sql clob := '';
begin
    for cur_tables in (select owner, table_name from all_tables where owner = v_owner and table_name in 
                       (select table_name from all_tab_columns where owner = all_tables.owner and data_type like '%' ||  upper(v_data_type) || '%')
                       order by table_name) loop
        v_counter := 0;
        v_sql := '';

        for cur_columns in (select column_name from all_tab_columns where 
                            owner = v_owner and table_name = cur_tables.table_name and data_type like '%' || upper(v_data_type) || '%') loop
            if v_counter > 0 then
                v_sql := v_sql || ' or ';
            end if;
            v_sql := v_sql || 'upper(' || cur_columns.column_name || ') like ''%' || upper(v_search_string) || '%''';
            v_counter := v_counter + 1;
        end loop;

        v_sql := 'select count(*) from ' || cur_tables.table_name || ' where ' || v_sql;

        execute immediate v_sql
        into v_match_count;

        if v_match_count > 0 then
            dbms_output.put_line('Match in ' || cur_tables.owner || ': ' || cur_tables.table_name || ' - ' || v_match_count || ' records');
        end if;
    end loop;

    exception
        when others then
            dbms_output.put_line('Error when executing the following: ' || dbms_lob.substr(v_sql, 32600));
end;
/

回复于 2024-05-14T19:49:20+08:00

我会做这样的事情（生成你需要的所有选择） . 您可以稍后将它们提供给sqlplus：

echo "select table_name from user_tables;" | sqlplus -S user/pwd | grep -v "^--" | grep -v "TABLE_NAME" | grep "^[A-Z]" | while read sw;
do echo "desc $sw" | sqlplus -S user/pwd | grep -v "\-\-\-\-\-\-" | awk -F' ' '{print $1}' | while read nw;
do echo "select * from $sw where $nw='val'";
done;
done;

它产生：

select * from TBL1 where DESCRIPTION='val'
select * from TBL1 where ='val'
select * from TBL2 where Name='val'
select * from TBL2 where LNG_ID='val'

它的作用是 - 从 user_tables 每个 user_tables 获取每个字段（来自desc）并从表中创建一个select *，其中field等于'val' .

回复于 2024-05-14T19:49:20+08:00

我对@Lalit Kumars的回答有以下问题，

ORA-19202: Error occurred in XML processing
ORA-00904: "SUCCESS": invalid identifier
ORA-06512: at "SYS.DBMS_XMLGEN", line 288
ORA-06512: at line 1
19202. 00000 -  "Error occurred in XML processing%s"
*Cause:    An error occurred when processing the XML function
*Action:   Check the given error message and fix the appropriate problem

解决方案是：

WITH  char_cols AS
  (SELECT /*+materialize */ table_name, column_name
   FROM   cols
   WHERE  data_type IN ('CHAR', 'VARCHAR2'))
SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
       SUBSTR (table_name, 1, 14) "Table",
       SUBSTR (column_name, 1, 14) "Column"
FROM   char_cols,
       TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select "'
       || column_name
       || '" from "'
       || table_name
       || '" where upper("'
       || column_name
       || '") like upper(''%'
       || :val
       || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
ORDER  BY "Table"
/

回复于 2024-05-14T19:49:20+08:00

修改代码以使用LIKE查询不区分大小写，而不是查找完全匹配...

DECLARE
  match_count INTEGER;
  -- Type the owner of the tables you want to search.
  v_owner VARCHAR2(255) :='USER';
  -- Type the data type you're looking for (in CAPS). Examples include: VARCHAR2, NUMBER, etc.
  v_data_type VARCHAR2(255) :='VARCHAR2';
  -- Type the string you are looking for.
  v_search_string VARCHAR2(4000) :='Test';
BEGIN
  dbms_output.put_line( 'Starting the search...' );
  FOR t IN (SELECT table_name, column_name FROM all_tab_cols where owner=v_owner and data_type = v_data_type) LOOP
    EXECUTE IMMEDIATE 
    'SELECT COUNT(*) FROM '||t.table_name||' WHERE LOWER('||t.column_name||') LIKE :1'
    INTO match_count
    USING LOWER('%'||v_search_string||'%');
    IF match_count > 0 THEN
      dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
    END IF;
  END LOOP;
END;

回复于 2024-05-14T19:49:20+08:00

4

我没有关于SQL提示的简单解决方案 . 但是有很多像toad和PL / SQL Developer这样的工具都有一个用户可以输入要搜索的字符串的GUI，它将返回找到它的表/过程/对象 .

回复于 2024-05-14T19:49:20+08:00

从this Blog post借用，略微增强和简化以下简单的SQL语句似乎很好地完成了这项工作：

SELECT DISTINCT (:val) "Search Value", TABLE_NAME "Table", COLUMN_NAME "Column"
FROM cols,
     TABLE (XMLSEQUENCE (DBMS_XMLGEN.GETXMLTYPE(
       'SELECT "' || COLUMN_NAME || '" FROM "' || TABLE_NAME || '" WHERE UPPER("'
       || COLUMN_NAME || '") LIKE UPPER(''%' || :val || '%'')' ).EXTRACT ('ROWSET/ROW/*')))
ORDER BY "Table";

回复于 2024-05-14T19:49:20+08:00

我对上面的代码做了一些修改，如果你只搜索一个所有者，它可以更快地工作 . 您只需更改3个变量v_owner，v_data_type和v_search_string以适合您要搜索的内容 .

SET SERVEROUTPUT ON SIZE 100000

DECLARE
  match_count INTEGER;
-- Type the owner of the tables you are looking at
  v_owner VARCHAR2(255) :='ENTER_USERNAME_HERE';

-- Type the data type you are look at (in CAPITAL)
-- VARCHAR2, NUMBER, etc.
  v_data_type VARCHAR2(255) :='VARCHAR2';

-- Type the string you are looking at
  v_search_string VARCHAR2(4000) :='string to search here...';

BEGIN
  FOR t IN (SELECT table_name, column_name FROM all_tab_cols where owner=v_owner and data_type = v_data_type) LOOP

    EXECUTE IMMEDIATE 
    'SELECT COUNT(*) FROM '||t.table_name||' WHERE '||t.column_name||' = :1'
    INTO match_count
    USING v_search_string;

    IF match_count > 0 THEN
      dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
    END IF;

  END LOOP;
END;
/

回复于 2024-05-14T19:49:20+08:00

这是另一个修改版本，它将比较较低的子字符串匹配 . 这适用于Oracle 11g .

DECLARE
  match_count INTEGER;
-- Type the owner of the tables you are looking at
  v_owner VARCHAR2(255) :='OWNER_NAME';

-- Type the data type you are look at (in CAPITAL)
-- VARCHAR2, NUMBER, etc.
  v_data_type VARCHAR2(255) :='VARCHAR2';

-- Type the string you are looking at
  v_search_string VARCHAR2(4000) :='%lower-search-sub-string%';

BEGIN
  FOR t IN (SELECT table_name, column_name FROM all_tab_cols where owner=v_owner and data_type = v_data_type) LOOP

    EXECUTE IMMEDIATE 
    'SELECT COUNT(*) FROM '||t.table_name||' WHERE lower('||t.column_name||') like :1'
    INTO match_count
    USING v_search_string;

    IF match_count > 0 THEN
      dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
    END IF;

  END LOOP;
END;
/

回复于 2024-05-14T19:49:20+08:00

我知道这是一个古老的话题 . 但我看到一个问题的评论，询问是否可以在 SQL 中完成，而不是使用 PL/SQL . 所以想发布一个解决方案 .

以下演示是Search for a VALUE in all COLUMNS of all TABLES in an entire SCHEMA：

搜索 CHARACTER type

让我们在 SCOTT 架构中查找值 KING .

SQL> variable val varchar2(10)
SQL> exec :val := 'KING'

PL/SQL procedure successfully completed.

SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
  2    SUBSTR (table_name, 1, 14) "Table",
  3    SUBSTR (column_name, 1, 14) "Column"
  4  FROM cols,
  5    TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
  6    || column_name
  7    || ' from '
  8    || table_name
  9    || ' where upper('
 10    || column_name
 11    || ') like upper(''%'
 12    || :val
 13    || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
 14  ORDER BY "Table"
 15  /

Searchword  Table          Column
----------- -------------- --------------
KING        EMP            ENAME

SQL>

搜索 NUMERIC type

让我们在 SCOTT 架构中查找值 20 .

SQL> variable val NUMBER
SQL> exec :val := 20

PL/SQL procedure successfully completed.

SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
  2    SUBSTR (table_name, 1, 14) "Table",
  3    SUBSTR (column_name, 1, 14) "Column"
  4  FROM cols,
  5    TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
  6    || column_name
  7    || ' from '
  8    || table_name
  9    || ' where upper('
 10    || column_name
 11    || ') like upper(''%'
 12    || :val
 13    || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
 14  ORDER BY "Table"
 15  /

Searchword  Table          Column
----------- -------------- --------------
20          DEPT           DEPTNO
20          EMP            DEPTNO
20          EMP            HIREDATE
20          SALGRADE       HISAL
20          SALGRADE       LOSAL

SQL>

回复于 2024-05-14T19:49:20+08:00

28

有一些免费的工具可以进行这种搜索，例如，这个工作正常，源代码可用：https://sites.google.com/site/freejansoft/dbsearch

您需要Oracle ODBC驱动程序和DSN才能使用此工具 .

回复于 2024-05-14T19:49:20+08:00

搜索整个数据库的过程：

CREATE or REPLACE PROCEDURE SEARCH_DB(SEARCH_STR IN VARCHAR2, TAB_COL_RECS OUT VARCHAR2) IS
      match_count integer;
      qry_str varchar2(1000);
      CURSOR TAB_COL_CURSOR IS 
          SELECT TABLE_NAME,COLUMN_NAME,OWNER,DATA_TYPE FROM ALL_TAB_COLUMNS WHERE DATA_TYPE in ('NUMBER','VARCHAR2') AND OWNER='SCOTT';
          BEGIN  
            FOR TAB_COL_REC  IN TAB_COL_CURSOR
            LOOP
              qry_str := 'SELECT COUNT(*) FROM '||TAB_COL_REC.OWNER||'.'||TAB_COL_REC.TABLE_NAME|| 
              ' WHERE '||TAB_COL_REC.COLUMN_NAME;
               IF TAB_COL_REC.DATA_TYPE = 'NUMBER' THEN
                      qry_str := qry_str||'='||SEARCH_STR; 
               ELSE
                       qry_str := qry_str||' like '||SEARCH_STR; 
               END IF;
                       --dbms_output.put_line( qry_str );
                EXECUTE IMMEDIATE  qry_str  INTO match_count;
                IF match_count > 0 THEN          
                   dbms_output.put_line( qry_str );
                  --dbms_output.put_line( TAB_COL_REC.TABLE_NAME ||' '||TAB_COL_REC.COLUMN_NAME ||' '||match_count);     
                    TAB_COL_RECS := TAB_COL_RECS||'@@'||TAB_COL_REC.TABLE_NAME||'##'||TAB_COL_REC.COLUMN_NAME;
                END IF; 
          END LOOP;
     END SEARCH_DB;

执行声明

DECLARE
    SEARCH_STR VARCHAR2(200);
    TAB_COL_RECS VARCHAR2(200);
    BEGIN
      SEARCH_STR := 10;
      SEARCH_DB(
        SEARCH_STR => SEARCH_STR,
        TAB_COL_RECS => TAB_COL_RECS
      );
     DBMS_OUTPUT.PUT_LINE('TAB_COL_RECS = ' || TAB_COL_RECS);
     END;

样本结果

Connecting to the database test.
SELECT COUNT(*) FROM SCOTT.EMP WHERE DEPTNO=10
SELECT COUNT(*) FROM SCOTT.DEPT WHERE DEPTNO=10
TAB_COL_RECS = @@EMP##DEPTNO@@DEPT##DEPTNO
Process exited.
Disconnecting from the database test.

回复于 2024-05-14T19:49:20+08:00

6
是的，你可以和你的DBA讨厌你，并且会发现你将你的鞋子钉在地板上，因为这会导致大量的I / O并且在缓存清除时真正降低数据库性能 .
```
select column_name from all_tab_columns c, user_all_tables u where c.table_name = u.table_name;
```
作为一个开始 .

我将从运行的查询开始，使用 v$session 和 v$sqlarea . 这基于oracle版本而变化 . 这将缩小空间范围，而不是打击一切 .
回复于 2024-05-14T19:49:20+08:00

运行完成 - 没有错误

SET SERVEROUTPUT ON SIZE 100000

DECLARE
   v_match_count     INTEGER;
   v_counter         INTEGER;




v_owner           VARCHAR2 (255) := 'VASOA';
v_search_string   VARCHAR2 (4000) := '99999';
v_data_type       VARCHAR2 (255) := 'CHAR';
v_sql             CLOB := '';

BEGIN
   FOR cur_tables
      IN (  SELECT owner, table_name
              FROM all_tables
             WHERE     owner = v_owner
                   AND table_name IN (SELECT table_name
                                        FROM all_tab_columns
                                       WHERE     owner = all_tables.owner
                                             AND data_type LIKE
                                                       '%'
                                                    || UPPER (v_data_type)
                                                    || '%')
          ORDER BY table_name)
   LOOP
      v_counter := 0;
      v_sql := '';

      FOR cur_columns
         IN (SELECT column_name, table_name
               FROM all_tab_columns
              WHERE     owner = v_owner
                    AND table_name = cur_tables.table_name
                    AND data_type LIKE '%' || UPPER (v_data_type) || '%')
      LOOP
         IF v_counter > 0
         THEN
            v_sql := v_sql || ' or ';
         END IF;

         IF cur_columns.column_name is not null
         THEN
            v_sql :=
                  v_sql
               || 'upper('
               || cur_columns.column_name
               || ') ='''
               || UPPER (v_search_string)||'''';

            v_counter := v_counter + 1;
         END IF;

      END LOOP;

      IF v_sql is  null
      THEN
         v_sql :=
               'select count(*) from '
            || v_owner
            || '.'
            || cur_tables.table_name;

      END IF;

      IF v_sql is not null
      THEN
         v_sql :=
               'select count(*) from '
            || v_owner
            || '.'
            || cur_tables.table_name
            || ' where '
            || v_sql;
      END IF;

      --v_sql := 'select count(*) from ' ||v_owner||'.'|| cur_tables.table_name ||' where '||  v_sql;


      --dbms_output.put_line(v_sql);
      --DBMS_OUTPUT.put_line (v_sql);

      EXECUTE IMMEDIATE v_sql INTO v_match_count;

      IF v_match_count > 0
      THEN
        DBMS_OUTPUT.put_line (v_sql);
        dbms_output.put_line('Match in ' || cur_tables.owner || ': ' || cur_tables.table_name || ' - ' || v_match_count || ' records');
      END IF;

   END LOOP;
EXCEPTION
   WHEN OTHERS
   THEN
      DBMS_OUTPUT.put_line (
            'Error when executing the following: '
         || DBMS_LOB.SUBSTR (v_sql, 32600));
END;
/

回复于 2024-05-14T19:49:20+08:00

如果我们知道表和列名称但想要找出每个模式出现字符串的次数：

Declare

owner VARCHAR2(1000);
tbl VARCHAR2(1000);
cnt number;
ct number;
str_sql varchar2(1000);
reason varchar2(1000);
x varchar2(1000):='%string_to_be_searched%';

cursor csr is select owner,table_name 
from all_tables where table_name ='table_name';

type rec1 is record (
ct VARCHAR2(1000));

type rec is record (
owner VARCHAR2(1000):='',
table_name VARCHAR2(1000):='');

rec2 rec;
rec3 rec1;
begin

for rec2 in csr loop

--str_sql:= 'select count(*) from '||rec.owner||'.'||rec.table_name||' where CTV_REMARKS like '||chr(39)||x||chr(39);
--dbms_output.put_line(str_sql);
--execute immediate str_sql

execute immediate 'select count(*) from '||rec2.owner||'.'||rec2.table_name||' where column_name like '||chr(39)||x||chr(39)
into rec3;
if rec3.ct <> 0 then
dbms_output.put_line(rec2.owner||','||rec3.ct);
else null;
end if;
end loop;
end;

回复于 2024-05-14T19:49:20+08:00

2
引用：

我尝试使用下面的语句根据我认为应该命名的内容找到一个合适的列，但它没有返回结果 . * SELECT * from dba_objects WHERE
object_name类似'％DTN％'

列不是对象 . 如果您的意思是您希望列名称与'％DTN％'相似，那么您想要的查询是：
```
SELECT owner, table_name, column_name FROM all_tab_columns WHERE column_name LIKE '%DTN%';
```
但如果“DTN”字符串只是你自己的猜测，那可能无济于事 .

顺便说一句，你有多确定'1/22 / 2008P09RR8'是直接从一列中选择的值？如果您根本不知道它来自哪里，它可能是多个列的串联，或某些函数的结果，或者是嵌套表对象中的值 . 因此，您可能正在进行疯狂的追逐尝试检查每个列的值 . 您是否可以从任何客户端应用程序显示此值开始，并尝试找出它用于获取它的查询？

无论如何，diciu的答案提供了一种生成SQL查询的方法，以检查每个表的每一列的值 . 您还可以使用PL / SQL块和动态SQL在一个SQL会话中完全执行类似的操作 . 这是一些草率编写的代码：
```
SET SERVEROUTPUT ON SIZE 100000

    DECLARE
      match_count INTEGER;
    BEGIN
      FOR t IN (SELECT owner, table_name, column_name
                  FROM all_tab_columns
                  WHERE owner <> 'SYS' and data_type LIKE '%CHAR%') LOOP

        EXECUTE IMMEDIATE
          'SELECT COUNT(*) FROM ' || t.owner || '.' || t.table_name ||
          ' WHERE '||t.column_name||' = :1'
          INTO match_count
          USING '1/22/2008P09RR8';

        IF match_count > 0 THEN
          dbms_output.put_line( t.table_name ||' '||t.column_name||' '||match_count );
        END IF;

      END LOOP;

    END;
    /
```
有一些方法可以使它更有效率 .

在这种情况下，给定您要查找的值，您可以清楚地删除任何NUMBER或DATE类型的列，这将减少查询的数量 . 甚至可能将其限制为类型为'％CHAR％'的列 .

您可以，而不是每列一个查询每个表构建一个查询，如下所示：
```
SELECT * FROM table1
  WHERE column1 = 'value'
     OR column2 = 'value'
     OR column3 = 'value'
     ...
     ;
```
回复于 2024-05-14T19:49:20+08:00

搜索特定值的所有表中的所有字段（Oracle）

15 回答

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