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SQL使用select中的select来获取每年的结果

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我正在为我的SQL研究工作在northwind数据库，我试图每年显示购买量最大的客户 .

在我看来，我需要在一个选择中做一个选择，以获得我正在寻找工作的结果 . 我设法为客户获得最多的订单，但我不能订购它或者只是将它分开多年 .

这是我到目前为止所做的事情：

select top 1 
    (count([Order Details].OrderID)) 'NumOfOrders',
    Customers.CompanyName, year(OrderDate) 'OrderYear'
from 
    [Order Details], Orders, Customers
where 
    [Order Details].OrderID = Orders.OrderID 
    and Orders.CustomerID = Customers.CustomerID 
    and (year(OrderDate) = 1996 or year(OrderDate) = 1997 or year(OrderDate) = 1998)
group by 
    Customers.CompanyName, year(OrderDate)
order by 
    NumOfOrders desc
sql sql-server tsql

2 回答

  • 1

    如果从脚本中删除TOP 1，您将看到自己想要的内容 . 但戈登说，你需要提高你的查询技巧 . 我找到了一些链接，你可以检查一下：

    示例脚本：

    SELECT 
     C.CompanyName
    ,YEAR(O.OrderDate) AS 'OrderYear'
    ,(COUNT(O.OrderID)) AS 'NumOfOrders'
FROM [Order Details] AS OD
INNER JOIN Orders AS O ON OD.OrderID = O.OrderID
INNER JOIN Customers AS C ON O.CustomerID = C.CustomerID
WHERE   YEAR(O.OrderDate) IN(1996,1997,1998)
GROUP BY C.CompanyName
        ,YEAR(O.OrderDate)
ORDER BY 
        C.CompanyName
        ,YEAR(O.OrderDate)
        ,NumOfOrders DESC
    回复于
  • 1

    如果我能够正确理解您想要实现的目标（每年最有 Value 客户的前1名），那么您可以尝试这样做：

    SELECT  TOP 1 WITH TIES
        t.NumOfOrders, 
        t.CompanyName, 
        t.OrderYear,
        ROW_NUMBER() OVER (PARTITION BY t.OrderYear 
                            ORDER BY t.NumOfOrders DESC ) AS RN
FROM (  SELECT      COUNT(OD.OrderID) AS [NumOfOrders] ,
                    C.CompanyName,
                    YEAR(OrderDate) AS [OrderYear]
        FROM    [Order Details] AS OD 
                    JOIN [Orders] AS O ON OD.OrderID = O.OrderID
                    JOIN Customers AS C ON O.CustomerID = C.CustomerID
        WHERE  YEAR(OrderDate) IN (1996, 1997, 1998)
        GROUP BY C.CompanyName, YEAR(OrderDate)
     ) AS T
ORDER BY RN
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