如何在swift中检查时间重叠？

2 回答

• 1

  您可以为此用途扩展Range类，也可以在CGRect类上使用intersection .

  // CGRect用法

  var r1 = CGRect(x: 4.8, y: 0, width: 1.8, height: 1)
  var r2 = CGRect(x: 5.8, y: 0, width: 2, height: 1)
  var r3 = CGRect(x: 6, y: 0, width: 0.8, height: 1)
  
  r1.intersection(r2).intersection(r3)
  

  // ClosedRange用法

  extension CountableClosedRange where Bound == Int {
          func intersection(_ range: CountableClosedRange<Int>) -> CountableClosedRange<Int>? {
              if(self.lowerBound >= range.upperBound) {
                  return nil;
              }
              if(self.upperBound <= range.lowerBound) {
                  return nil;
              }
              return CountableClosedRange(uncheckedBounds:
                  (lower: self.lowerBound > range.lowerBound ?
                      self.lowerBound
                      :range.lowerBound,
                   upper: self.upperBound < range.upperBound ?
                      self.upperBound
                      :range.upperBound))
          }
      }
  
      func convertTime(h:Int, m: Int = 0) -> Int {
          return m+h*60;
      }
      var range1 = CountableClosedRange(uncheckedBounds: (lower: 48 , upper: 56))
      var range2 = CountableClosedRange(uncheckedBounds: (lower: 53 , upper: 55))
      var range3 = CountableClosedRange(uncheckedBounds: (lower: 45 , upper: 54))
      var range4 = CountableClosedRange(uncheckedBounds: (lower: 47 , upper: 64))
      let arr = [range2,range3,range4]
      var resultRange:CountableClosedRange<Int>? = range1
      for item in arr {
          resultRange = resultRange?.intersection(item)
      }
  

  回复于 2024-05-01T11:58:14+08:00
• 0

  你需要检查两个 Date 范围是否过度 . 这可以通过检查一个 ClosedRange<Date> 是否与另一个重叠来完成

  let isOverlapping = (startDate1...endDate1).overlaps(startDate2...endDate2)
  

  ---

  但对于您的情况，您不希望将此时间（在您的情况下为 Int index）附加到数组（如果它与数组中的任何其他时间重叠），因此在您附加此新时间之前检查是否与其他时间重叠 . 如果没有附加它，如果没有，做你想做的任何事情 .

  let array: [[String: Int]] = ...
  let newStartIndex: Int = ...
  let newEndIndex: Int = ...
  let isOverlapping = array.allSatisfy { $0["startTime"] <= newEndIndex && newStartIndex <= $0["stopTime"]}
  

  回复于 2024-05-01T11:58:14+08:00